X^2 - 7x + 12 = 0
x^2 - 4x - 3x + 12 = 0
x (x - 4) -3 ( x - 4) = 0
(x - 4) (x - 3) = 0
x = 3 , 4
Check the answer by plugging in 3 and 4 for x, if the equation equals zero then you have your answer.
Answer:
D
Step-by-step explanation:
We need to convert these words into mathematical expressions:
- "Twenty-two less than a number"; "less than" indicates that we need to use subtraction, and since it's "twenty-two less than", we have: -22. Let's say the "number" is q. Then, we have -22 of q, which is q - 22.
- "is twenty-four"; "is" in math always means "equal", so we need an equal sign with 24 next to it: = 24
Put this altogether:
q - 22 = 24
The answer is thus D.
Answer:
On a coordinate plane, a curve starts in quadrant 3 and then increases into quadrant 1. It crosses the y-axis at (0, negative 2) and crosses the x-axis at (1.5, 0)
Step-by-step explanation:
The attached graph is an example of the square root function scaled and translated.
_____
No transformation of the square root curve will turn it into a parabola or into two curves.
Standard form is another way of saying slope-intercept form. The equation you have there is in point-slope form, so we must convert this to slope-intercept form to get our final answer.
In point-slope form (y - k = m(x - h)) k is the y-value, h is the x-value, and m is the slope. All we must do is change your equation's form into standard form, or slope-intercept form which looks like this: (y = mx + b), where m is the slope and b is the y-intercept.
Convert this equation y + 1 = 2/3(x + 4) into standard/slope-intercept form.
y + 1 = 2/3(x + 4)
y + 1 = 2/3x + 2.666 Here we multiplied 2/3 by x and 4 since x + 4 is in parenthesis next to 2/3.
y + 1 - 1 = 2/3x + 2 2/3 - 1 Now we want to get y by itself so the form will look like y = mx + b, so we subtract the 1 from both sides of the equation. (2 2/3 is a mixed fraction that is equal to 2/3*4.)
y = 2/3x + 1 2/3
This is our final answer since it is in the standard, or slope-intercept form. Hope this made sense! If you have any questions please ask.
