Answer:
x + 2
Step-by-step explanation:
If we know one of the factors, we should be able to use long division.
We can divide the trinomial by the binomial and find the other factor.
<u>x + 2</u><u> </u>
x² + 4x + 3)x³ + 6x² + 11x + 6
<u>x³ + 4x² + 3x</u>
2x² + 8x + 6
<u>2x² + 8x + 6</u>
0
Thus,
![\dfrac{x^{3} + 6x^2 + 11x + 6} {x^{2} + 4x + 3} = \mathbf{x + 2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E%7B3%7D%20%2B%206x%5E2%20%2B%2011x%20%2B%206%7D%20%7Bx%5E%7B2%7D%20%2B%204x%20%2B%203%7D%20%3D%20%5Cmathbf%7Bx%20%2B%202%7D)
102.5
Lol, well to start, it’s not asking to divide 0.4 by 41. It’s asking to divide 41 by 0.4.
And that will get you to 102.5. You could do long division or use a calculator if you are allowed.
Answer:
a = -3
Step-by-step explanation:
3a - 6a + 2 = 8a + 20 - 5a
Combine Like Terms
-3a + 2 = 3a + 20
-2 -2
-------------------------------------
-3a = 3a + 18
-3a -3a
-------------------------------------
-6a = 18
---- ----
-6 -6
a = -3
Answer:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=5,−2
Step-by-step explanation:
I can do math
Ya what the person above me said