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siniylev [52]
3 years ago
14

A 31-foot support wire is attached from the top of a 25 foot telephone pole to a point on the ground. How far from the base pole

dose the wire meet the ground?
Mathematics
1 answer:
zlopas [31]3 years ago
3 0

Answer:

18.3

Step-by-step explanation:

approx. 18.3ft is the answer

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A triangle has a base of 54 cm. The height is unknown. Complete the equation that can be used to find the area, A, of the triang
Kay [80]

Answer:

A=1/2× base ×hieght

A=1/2×b×h

6 0
3 years ago
Pzz help! Gender is a type of which data?
qwelly [4]
DD continous quantitative
5 0
3 years ago
Read 2 more answers
The question is in the picture i attached. the right answer gets brainlist :) <3
sergeinik [125]

Answer:

∠ 4 = 130°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 4 is an exterior angle of the triangle , so

∠ 4 = ∠ 1 + ∠ 2 ( substitute values )

11x + 9 = 6x + 6 + 4x + 14 , that is

11x + 9 = 10x + 20 ( subtract 10x from both sides )

x + 9 = 20 ( subtract 9 from both sides )

x = 11

Then

∠ 4 = 11x + 9 = 11(11) + 9 = 121 + 9 = 130°

your friend may have only calculated ∠ 1

∠ 1 = 6x + 6 = 6(11) + 6 = 66 + 6 = 72°

7 0
2 years ago
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

8 0
3 years ago
Can someone help me asap
stealth61 [152]

Answer:

Option Y is correct.

Step-by-step explanation:

We are given the table representing the relation between new students and returning students for difference classes.

It is required to form the relative frequency table for the given situation.

So, relative frequency table is obtained by dividing the valued by the total number of values in the data set.

<em>Thus, we will get the relative frequency table by dividing the given table values by 500.</em>

Hence, we will get the following table,

                          New Students               Returning Students           Total

10th                         0.01                                   0.34                             0.35

11th                          0.006                                0.324                           0.33

12th                         0.004                                0.316                            0.32

Total                        0.02                                  0.98                                1

Thus, option Y is correct.

4 0
3 years ago
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