If the difference between two numbers is 12, those two numbers may be:
13...1
14...2
15...3
16...4
etc...
We can ignore numbers which can be divided by themselves (like 2...14 or 4...16), so we have:
13...1
17...5
19...7
20...8
21...9
22...10
Let's stop here and find LCMs of given numbers:
13...1 = 13
17...5 = 85
19...7 = 133
20...8 = 40
21...9 = 63
22...10 = 110
So as we can see the numbers we're looking for are 19 and 7.
This is my best guess from memory
20*16=320
8*square root of 3=13.9
320+13.9=333.9
Answer:
Step-by-step explanation:
(x²-6x-3)(7x²-4x+7)= ?
Multiply each term of 2nd bracket with the 1st bracket:
=7x²(x²-6x-3) -4x(x²-6x-3) +7(x²-6x-3)
=7x^4-42x^3-21x^2-4x^3+24x^2+12x+7x^2-42x-21
Now solve the like terms:
=7x^4-46x^3+10x^2-30x-21
Therefore the answer is (x²-6x-3)(7x²-4x+7)=7x^4-46x^3+10x^2-30x-21 ....
8Z = 64
Divide both sides by 8.
8Z/8 = 64/8
Z = 64/8
Z = 8
Your final answer is B. 8.
