WILL GIVE BRAINIEST ANSWER!!!Which of the following is true?

Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).

Korolek [52]

Answer:

$c = \dfrac{25}{4}$

$b = \dfrac{-13}{8}$

$a = \dfrac{11}{8}$

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

$c = \dfrac{25}{4}$

$b = \dfrac{-13}{8}$

$a = \dfrac{11}{8}$

6 0

3 years ago

i hate this website I ASKED ONE SINGLE QUESTION MORE THAN 5 TIMES WHICH IS UNACCEPTABLE. AND WHEN I DID GET HELP THE ANSWER WAS

Paladinen [302]

Answer:

Then maybe pay attention in class and know what to do and not ask strangers for help. We answer to try and help. Not like we get paid. We literally are just trying to help

6 0

3 years ago

What is the area of parallelogram rstu? 21 square units 24 square units 28 square units 32 square units

Ray Of Light [21]

The area of the considered parallelogram RTSU is given by: Option A: 21 sq. units

<h3>How to find the area of a parallelogram?</h3>

Area of a parallelogram = (its height × its base) sq. units.

<h3>What is the distance between two points ( p,q) and (x,y)?</h3>

The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

$D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units$

For this case, the missing diagram is attached below.

If we take the base as ST then as ST is parallel to y axis, the line perpendicular to ST would be parallel to x axis. The heigth of a parallogram is the perpendicular distance between its base and top.

The base is ST and top is RU, the line segment US is perpendicular to both RU and US and its length,therefore, will serve as height as its length=perpendicular distance between the base and the top of the parallelogram.

Thus, we get:

Area of RTSU = Length of ST × Length of US

The coordinates of endpoints of ST are (4,-1), (4,-4)

Thus, the length of ST = distance between S and T = $\sqrt{(4-4)^2 + (-1 - (-4))^2 }= 3$