There is a fifty percent chance of the coin landing on "heads" each time it is flipped.
However, flipping a coin 20 times virtually guarantees that it will land on "heads" at least once in that twenty times. <span>(99.9999046325684 percent chance)
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You can see this by considering two coin flips. Here are the possibilities:
Heads, heads.
Heads, tails.
Tails, tails.
Tails, heads.
You will note in the tossing of the coin twice that while each flip is
fifty/fifty, that for the two flip series, there are three ways that it
has heads come up at least once, and only one way in which heads does
not come up. In other words, while it is a fifty percent chance
for heads each time, it is a seventy five percent chance of seeing it
be heads once if you are flipping twice. If you wish to know
the odds of it not being heads in a twenty time flip, you would multiply
.5 times .5 times .5...twenty times total. Or .5 to the twentieth
power. That works out to a 99.9999046325684 percent chance of
it coming up heads at least once in the twenty times of it being
flipped.
Answer:
Alternative hypothesis is p1≠p2. Test Statistic is 0.1928.
There is no significant evidence to believe that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode at 0.01 significance level.
Step-by-step explanation:
The Question is missing. Full question is as follows:
It has been observed that some persons who suffer acute heartburn, again suffer acute heartburn within one year of the first episode. This is due, in part, to damage from the first episode. The performance of a new drug designed to prevent a second episode is to be tested for its effectiveness in preventing a second episode.In order to do this two groups of people suffering a first episode are selected. There are 55 people in the first group and this group will be administered the new drug. There are 75 people in the second group and this group will be administered a placebo. After one year, 10% of the first group has a second episode and 9% of the second group has a second episode. Conduct a hypothesis test to determine, at the significance level 0.01,whether there is reason to believe that the true percentage of those in the first group who suffer a second episode is different from the true percentage of those in the second group who suffer a second episode? Select the [Alternative Hypothesis, Value of the Test Statistic].
Let p1 be the proportion of the first group who has second episode
Let p2 be the proportion of the second group who has second episode
p1≠p2
z-statistic of the test can be found using the formula
z= where
- p1 is the sample proportion of the first group who has second episode (0.1 or 10%)
- p2 is the sample proportion of the second group who has second episode(0.09 or 9%)
- p is the pool proportion of p1 and p2 (0.09423)
- n1 is the sample size of the first group (55)
- n2 is the sample size of the second group (75)
Then
z=
≈ 0.1928 corresponding two tailed p-value p(z) is 0.8471.
Since p(z)>0.1 we fail to reject the null hypothesis and conlude that p1=p2 at 0.01 significance.
You have to add .7+.7+5+5=11.4
Answer:
y = x - 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x ← is in slope- intercept form
with slope m = - , c = 0
Given a line with slope m then the slope of a line perpendicular to it is
= - = - = , then
y = x + c ← is the partial equation
To find c substitute (3, - 8) into the partial equation
- 8 = 4 + c ⇒ c = - 8 - 4 = - 12
y = x - 12 ← equation of perpendicular line
Volume is length x width x height.
Volume = 5 x 5 x 5.5
Volume = 137.5 cubic inches.