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Nata [24]
4 years ago
14

A 2-digit number is 12 times its tens digit. The sum of the digits is 12. What is the tens digit?

Mathematics
2 answers:
Goryan [66]4 years ago
8 0
C) or 2 is the solution to your question c:
LekaFEV [45]4 years ago
8 0
Yeah their right its C
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If no number can be used more than once, how many different 2-digit numbers can be formed from the digits 4, 6, and 8?
ikadub [295]

Answer:

Six.

46

48

64

68

84

86

Step-by-step explanation:

hoped this helped!

4 0
3 years ago
Through (7,2); parallel to 3x-y=8.
Dovator [93]

Answer:

x=4 y=4

Step-by-step explanation:

4 0
3 years ago
What is the value of x
amm1812

Answer:

x=123

Step-by-step explanation:

x is across from the angle that measures 123 degrees. Therefore, they are vertical angles, and are congruent.

x=123

Additionally, 57 and x are on a straight line. This means they are supplementary and add to 180 degrees

57*x=180

Subtract 57 from both sides to get x by itself.

x=123

6 0
3 years ago
A well mixed tank with a capacity of 1500 gals originally contains 1000 gallons of freshwater. One pipe containing 1/2 lb of sal
Illusion [34]

Answer:

400 lb of salt

Step-by-step explanation:

Let us assume the water flows into the rank for x minutes.

There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x

Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x

The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:

1500 = 1000 + 5x

5x = 1500 - 1000

5x = 500

x = 100 minutes.

1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb

Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt

7 0
4 years ago
Circle A is shown. Tangents L M and N M intersect at point M outside of the circle. Arc L N is 270 degrees. In the diagram of ci
luda_lava [24]

Answer:

\angle m=90^o

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The measurement of the external angle is the half-difference of the arches that comprise

so

\angle m=\frac{1}{2}(major\ arc\ LN-minor\ arc\ LN)

Remember that the sum of the major arc and a minor arc is equal to 360 degrees

we have

major\ arc\ LN=270^o ----> is given

so

minor\ arc\ LN=360^o-270^o=90^o

substitute the values

\angle m=\frac{1}{2}(270^o-90^o)=90^o

5 0
4 years ago
Read 2 more answers
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