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MissTica
2 years ago
11

"All rational functions have asymptotes and points of discontinuity." Katlyn wants to put this statement in her math book. Is th

is statement true? Explain, for her benefit, using 2 examples
Mathematics
1 answer:
scZoUnD [109]2 years ago
6 0

Answer:

Not true.

Step-by-step explanation:

A  rational function is like P(x) / Q(x) where P and Q are polynomials.

Examples would be x^2 / (x^2 - 2)  and  x^2 / (x^2 + 2).

Now the first one will have a vertical asymptote at x = √2 because this value would make the denominator zero.

The second one will have no asymptotes because the only value that would make x^2 + 2 = zero is not real (it would be √2i). So the domain of this  is all real numbers ,  and  no asymptotes.

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Step-by-step explanation:

hope this helps!

7 0
3 years ago
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