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Kazeer [188]
3 years ago
11

A school sold brownies and cupcakes at a bake sale. There were 592 total items available for sale. All 286 brownies were sold. O

f the cupcakes for sale, 49 did not sell. How many cupcakes did sell at the bake sale? Select the correct equation to solve. A. 592 - 286 - 49 = c B. 592 - 286 + 49 = c C. 592 + 286 - 49 = c
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0

Answer:

A. 592 - 286 - 49 = c

Step-by-step explanation:

A school sold brownies and cupcakes at a bake sale. There were 592 total items available for sale. All 286 brownies were sold. Of the cupcakes for sale, 49 did not sell. How many cupcakes did sell at the bake sale?

Total number = 592

Total number of brownies = 286

The cup cakes for sale = 592 - 286

= 306 cupcakes.

49 of the cupcakes did not sell

The cupcakes that sold = 306 - 49

= 257 cupcakes were sold.

Therefore, the correct equation to solve. A. 592 - 286 - 49 = c

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Timothy creates a game in which the player rolls 4 dice. What is the probability in this game of having exactly two dice or more
devlian [24]

Answer:

B. 0.132

Step-by-step explanation:

For each time the dice is thrown, there are only two possible outcomes. Either it lands on a five, or it does not. The probability of a throw landing on a five is independent of other throws. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Timothy creates a game in which the player rolls 4 dice.

This means that n = 4

The dice can land in 6 numbers, one of which is 5.

This means that p = \frac{1}{6}

What is the probability in this game of having exactly two dice or more land on a five?

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(\frac{1}{6})^{2}.(\frac{5}{6})^{2} = 0.116

P(X = 3) = C_{4,2}.(\frac{1}{6})^{3}.(\frac{5}{6})^{1} = 0.015

P(X = 4) = C_{4,4}.(\frac{1}{6})^{4}.(\frac{5}{6})^{0} = 0.001

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.116 + 0.015 + 0.001 = 0.132

So the correct answer is:

B. 0.132

8 0
3 years ago
for any numbers x,y [x=0 in(4) and y = 0 in (5)] and any positive integers m,n, the following holds:x^m · x^n=x^m+nProve number
AlladinOne [14]

Proved

Explanation:

To prove x^m · x^n=x^m+n, let's assign numbers to x, m and n

let x = 2

m = 3, n = 4

x^m · x^n = 2^3 . 2^4

x^m+n = 2^(3+4)

Solve each of the above seperately and comparew the answer:

\begin{gathered} x^m\times x^n=2^3\times2^4 \\ =\text{ (2}\times2\times2)\times(2\times2\times2\times2) \\ =\text{ 8}\times16 \\ =\text{ }128 \end{gathered}\begin{gathered} x^{m+n}=2^{3+4} \\ =2^7\text{ = 2}\times2\times2\times2\times2\times2\times2 \\ =\text{ 128} \end{gathered}\begin{gathered} sincex^m\times x^n\text{ = 128} \\ \text{and x}^{m+n}\text{ = 128} \\ \text{Therefore, }x^m\times x^n\text{ =  x}^{m+n} \end{gathered}

This expression x^m · x^n=x^m+n has been proved to be equal

4 0
1 year ago
The length and breadth of a rectangle are in the ratio 4:3. Its area is 300sq.cm. Find its length and breadth.
ziro4ka [17]

Step-by-step explanation:

4:3

4+3=7

4x + 3x= 7x

7x is the total sq.cm which is 300

7x= 300

x= 300/7

= 42.8

length= 4x

= 4 × 42.8

= 171.42

breadth= 3x

= 3 × 42.8

= 128.4

4 0
2 years ago
If you put $603 in a savings account that pays 9% for one year what is the amount of money that you will have at the end of the
velikii [3]
The answer would be 657.27$
you would need to multiply 603 by 0.09 (which is 9%) and then add 603 to it. that’s how i did it. hope this helps
5 0
3 years ago
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Gabriella needs a mason and must decide between 2 companies. For a service visit, Company A charges $65 to send a mason plus $30
Kamila [148]
So first we write out their respective charges
A=65+30x (x=hours of A)
B=30+47.5y (x= hours of B)

we want to know when A and B are equal so just set them to be equal

65+30x=30+47.5x
subtract 30 from both sides
35+30x=47.5x
multiplyboth sides by 2 to get rid of the nasty decimal
70+60x=95x
subtract 60x from both sides
70=35x
divide both sides by 35
2=x
they must work 2 hours for them to be equal

7 0
4 years ago
Read 2 more answers
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