All categories

3 years ago

If pedro has five milk jugs, then he gives 3 away too charity how many more does he have?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

6 0

Ok so you take 5 minus 3 which is 2.
So pedro has 2 milk jugs left

You might be interested in

Solve the in quality x plus 1<7

RUDIKE [14]

Answer:

x<6

Step-by-step explanation:

x+1 < 7

Subtract 1 from each side

x+1-1<7-1

x <6

7 0

2 years ago

The number of stories in each of a sample of the world’s 28 tallest buildings follows. Construct a grouped frequency distributio

Masja [62]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

54 79 100 70 75 56 88

55 78 75 55 72 60 80

55 88 80 85 69 71 60

90 64 77 88 65 102 70

Class____frequency____cumulative frequency

54 - 63_____7_____________7

64 - 73_____7_____________14

74 - 83_____7_____________21

84 - 93_____5_____________26

94 - 103____2_____________28

5 0

3 years ago

According to Section 7, all bills for raising revenue shall originate in the ___.

Airida [17]

House of Representatives. :)

7 0

3 years ago

One bushel of apples weighs 22<br> kilograms. How many kilograms<br> do 5.7 bushels weigh?

Solnce55 [7]

Answer:

125.4 kg

Step-by-step explanation:

I attached a picture of my work and I stuck it into my calculator to check it

5 0

3 years ago

According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou

Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

$p=X/n=35/140=0.25$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239$

We calculate the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198$

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

$P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183$

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

$p=X/n=21/140=0.15$

We can calculate then the z-score as:

$z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906$

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

$P(X$

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231$

We can calculate the z-scores for p1=0.18 and p2=0.25:

$z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651$

We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

$P=P(0.18$

5 0

3 years ago