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Murrr4er [49]
3 years ago
9

If 5 pizza cost 60$ how much would 15 pizzas cost

Mathematics
2 answers:
igomit [66]3 years ago
6 0
15 pizzas would cost $180.
LiRa [457]3 years ago
6 0

Answer:$180

Step-by-step explanation: 15 divided by 5= 3x60=$180

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Tamara invests $8000 in two different accounts. The first account has a simple interest rate of 3% and the second account has a
34kurt

Let Tamara invests amount X in 3% account. She invests 8000-X in 2% account.

The interest after t years is given by

I=Prt. After 1 year the two interests are equal, that is

X(\frac{3}{100}) (1)=(8000-X)(\frac{2}{100}) (1)\\ 3X=2(8000-X)\\ 5X=16000\\ X=3200

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4 0
3 years ago
In an effort to make childrenâs toys safer and more tamperproof, toy packaging has become cumbersome for parents to remove in ma
Monica [59]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Old design samples(n1) = 220

New design samples (n2) = 220

P1 = 81/220 = 0.368 ; P2 = 41/220 = 0.186

Null hypothesis : p1 - p2 ≥ 0.05

Alternative hypothesis : p1 - p2 < 0.05

Using the test statistic formula :

t = (P1 - P2) / √[P(1-P)(1/n1 + 1/n2)]

P = (81 + 41)/(220 + 220) = 122/440 = 0.277

1 - P = 0.723

t = (0.368 - 0.186) / (√(0.277(0.723)(1/220 + 1/220)))

t = 4.265

P value from z test at α = 0.05

P value = 0.00002

Test for significance at α = 0.01 ;

Test for significance at α = 0.1

Result is significant at both α levels, hence reject the Null.

5 0
3 years ago
Graph f(x) = (1/3)^x+1<br>​
e-lub [12.9K]

Answer:

The graph is attached below.

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(1/3\right)^x+1

Exponentiation function have a horizontal Asymptotes.

<u />

<u>Finding the horizontal Asymptotes</u>

<u />\mathrm{Exponential\:function\:of\:the\:form}\:f\left(x\right)\:=c\cdot \:n^{ax+b}+k\:<u />

<u />\mathrm{has\:a\:horizontal\:asymptote}\:y=k\:<u />

<u />k=1<u />

<u />\mathrm{The\:horizontal\:asymptote\:is:}<u />

<u />y=1<u />

<u />

<u>Finding y-intercepts</u>

<u />y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0<u />

<u />y=\left(\frac{1}{3}\right)^0+1<u />

<u />\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0<u />

<u />\left(\frac{1}{3}\right)^0=1<u />

<u />y=1+1<u />

<u />\mathrm{Add\:the\:numbers:}\:1+1=2<u />

<u />y=2<u />

\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)

The graph is attached below.

4 0
3 years ago
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