(100-15=85%)
85=101.15 how about 100
100 x 101.15 divided by 85=118.882353
$119
Answer:
x = 0.3, y = 5.3, z = 17.3
Step-by-step explanation:
Since given question is incomplete, so here is the complete table for the distance from the mean.
Temp (°F) 29 38 45 31 50 58 62
Distance from the mean 15.7 6.7 x 13.7 y 13.3 z
It's given that the mean of the data is 44.7
Since distance from the mean of a data is the absolute value of the difference of data and mean,
Therefore, distance from the mean of the data will be,
x = |44.7 - 45| = 0.3 (absolute value of the difference)
y = |44.7 - 50| = 5.3
z = |44.7 - 62| = 17.3
40.0*10 is the answer
actually it is 400 but u want in decimal so it is 40.0*10
Answer:
2 units
Step-by-step explanation:
Answer:

Step-by-step explanation:
![36-\left[100\div \:560-32\left(8\div \:4-1\right)\right]\\\\100\div \:560-32\left(8\div \:4-1\right)\\\\=100\div \:560-32\cdot \:1\\\\=\frac{100}{560}-32\cdot \:1\\\\=\frac{100}{560}-32\\\\=-\frac{891}{28}\\\\\\=36-\left(-\frac{891}{28}\right)\\\\36-\left(-\frac{891}{28}\right)\\\\=36+\frac{891}{28}\\\\\frac{36\cdot \:28}{28}+\frac{891}{28}\\\\\frac{36\cdot \:28+891}{28}\\\\=\frac{1899}{28}\\\\\\\frac{1899}{28}(1899\div28)=67\frac{23}{28}](https://tex.z-dn.net/?f=36-%5Cleft%5B100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5Cright%5D%5C%5C%5C%5C100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5C%5C%5C%5C%3D100%5Cdiv%20%5C%3A560-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5C%5C%5C%5C%3D-%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5C%5C%3D36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C%3D36%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%7D%7B28%7D%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%2B891%7D%7B28%7D%5C%5C%5C%5C%3D%5Cfrac%7B1899%7D%7B28%7D%5C%5C%5C%5C%5C%5C%5Cfrac%7B1899%7D%7B28%7D%281899%5Cdiv28%29%3D67%5Cfrac%7B23%7D%7B28%7D)