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2 years ago

What is one point that lies in the solution set of the system of inequalities graphed below?

Mathematics

1 answer:

Lunna [17]2 years ago

8 0

Answer:

(7, 0).

Step-by-step explanation:

Where the diagonal lines overlap to form squares is where the solutions to the inequality lies.

The point (7, 0) lies in that region.

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(SAT Prep) Find the value of x.

photoshop1234 [79]

Answer:

Step-by-step explanation:

I think

6 0

3 years ago

Read 2 more answers

Ms.Smith has 28 sixth graders and 42 seventh graders for math. If she wants to break the two grades into identical groups withou

Zinaida [17]

Add the 28 and 42
then divide by 2
there should be 35 kids in group

4 0

3 years ago

Solve the equation <br> 1/6(12z-18)=2z-3

Romashka-Z-Leto [24]

1/6(12z-18)=2z-3

12/6z-18/6 =2z-3

2z-3=2z-3

there are infinite solutions for this equation or all real numbers

8 0

3 years ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

3 years ago

A candy store held a contest to guess the total number of jelly beans in a jar. All of the jelly beans in the jar were either gr

Fudgin [204]

Answer:

Step-by-step explanation:

Let the number of orange jelly beans be x , as we do not know the exact value of it yet. There are 12 times as many green jelly beans than the orange ones. So , if the number of orange jelly beans is x , the number of green jelly beans will be = 12 times x , which can be written as 12x. Now there are a total of 1872 jelly beans , but they are either orange or green , so we already know that the number of orange jbs is x , and the number of green jelly beans is 12x. So if we the green jelly beans and orange jelly beans , it should be 1872.

Now all we need to do is to find x.

We know that ,

x + 12x = 1872

Now we add x and 12x on the left hand side

13x = 1872

Now we divide both sides by 13 to get x. (That includes 1872 as well)

x = 144

Now we have the value of x which is 144

We know that the number of green jelly beans was 12 times x

So the number of green jelly beans in numeric value is : 12 * 144

As x is equal to 144

Ans . : The number of green jelly beans is 1728.

6 0

3 years ago