<u>Answer:</u>
The correct answer option is D. set the switch to the highest range and then move it to a range that gives the most accurate reading.
<u>Explanation:</u>
When measuring an unknown voltage with an analog VOM, one should set the meter to the highest range and then move it to a range that gives the most accurate reading.
The reason being that the analog meters indicate the measurement of voltage by moving a needle across a physical card by printing numbers on it.
So in case the voltage is nearly 100 times the full range to which the meter is set, then its needle will try move to a position which will be 100 times the highest number on the meter.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
Answer:
C. Use the SOAP API to maintain the related SObject_share records
The limit for file names on modern file systems is usually at least 255 bytes.
Answer:
The answer is "option B".
Explanation:
In the given code, four double variable "len1, len2, len3, and total" is declared, in which the first three variables accept some value, and in the total variable, we add those variable. In the next step, an integer variable minLength is defined, which converts the decimal value to an integer and adds the value that is "0.5". In this section, the code uses as an intended purpose but only if the total of 3 lengths is equivalent to or larger then 0.5, and wrong choices can be described as follows:
- In option A, It accepts the negative value, that's why it is wrong.
- Option C, Option D, and Option E all were wrong because the code segment is work as intended.
