Answer:
D) extents
Explanation:
Disks fragmentations in computer science refers to the cases of a file system laying out its contents in a non-continuous manner thus preventing an in-place alteration of the contents (that is the contents of the file are scattered in fragments across different location on the disk). Disk fragmentation is mostly associated with aging. To mitigate against this, modern implementation of file systems try to preallocate longer chunks of disk space, this is called extents, in this way fragmentation is avoided since a contiguous size of disk space is preallocated to the files and its contents stay together.
Whenever you create a new slide, it appears below the selected slide.
If you have 2 slides and want one in between the two select the first slide and then select new slide.
The answer is:
Left
The backspace key only deletes whatever way the point is pointing to. In this case, it is to the left.
Correct me if i'm wrong.
Answer:
#include <iostream>
using namespace std;
int main() {
int *ip_arr,n;//pointer name inp_arr and integer n to store the size.
cin>>n;//size.
for(int i=0;i<n;i++)
ip_arr[i]=-1;//assigning -1 to every element.
for(int i=0;i<n;i++)
{
cout<<ip_arr[i]<<" ";//printing every element.
}
return 0;
}
output:-
100
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1
Explanation:
I am taking input of size.You should enter 100 for 100 values which have value -1.
Answer:
The correct answer for the given question is " roll1>3 || roll2 > 3 "
Explanation:
In option A, there are two conditions separated by OR. In OR, if any condition is true then it will return TRUE. There second condition is TRUE in the statement that is why the whole expression return TRUE.
Thats why the correct answer is "roll1>3 || roll2 > 3".
