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mixas84 [53]
3 years ago
14

13/20-3/10 estimate: closer to 1 or 0?

Mathematics
2 answers:
shusha [124]3 years ago
8 0
\frac{13}{20}\frac{12}{20}=\frac{6}{10}\\ \\\frac{6}{10}
dexar [7]3 years ago
6 0
So, what you need to is find the decimal or percent of them. So 13/20 is 65% or .65. You get that buy multiplying it by 5 to get the denominator of 100. A denominator can go up to 100. 13/20 is closer to 1 because 65% is closer to 100% than 0%. Next 3/10 is 30%. Do that by multiplying it by 10 to get the denominator of 100. 30% is closer to 0 than 100%. Subtract them. 1-0= 1. The answer is 1.
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Which diagram shows the percent equivalent to 3/5
Minchanka [31]

Answer:

the last one

Step-by-step explanation:

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If Bill was traveling v mi/h, how would you represent Daemon's speed in mi/h if he was traveling 45 mi/h faster?
VikaD [51]

The sum of two variables having the same units is given by adding the magnitudes of the quantities and expressing the outcome in the units of the quantities

Daemon's speed is (v + 45) mi/h

The reason the above value for Daemon's speed is correct is as follows:

The known parameters are;

The speed with which Bill was travelling = v mi/h

The speed with which Daemon was travelling = 45 mi/h faster than Bill

Method:

By dimensional analysis, we note that the given quantities have the same units, and therefore, they represent the same quantity of speed

To find Daemon's speed, the amount by which his speed is more than that of Bill's speed is added to the given amount of Bill's speed as follows;

Solution:

Daemon's speed = v mi/h + 45 mi/h = (v + 45) mi/h

Learn more about variable addition here:

brainly.com/question/22965573

brainly.com/question/242905

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3 years ago
Please answer this Square and Square Root question (at least one)
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3 0
3 years ago
Solve this equation log3X + log3(x-6) = log3 7
ExtremeBDS [4]

Hello!

log₃(x) + log₃(x - 6) = log₃(7) <=>

<=> log₃(x * (x - 6)) = log₃(7) <=>

<=> log₃(x² - 6x) = log₃(7) <=>

<=> x² - 6x = 7 <=>

<=> x² - 6x - 7 = 0 <=>

<=> x² + x - 7x - 7 = 0 <=>

<=> x * (x + 1) - 7 * (x + 1) = 0 <=>

<=> (x + 1) * (x - 7) = 0 <=>

<=> x + 1 = 0 and x - 7 = 0 <=>

<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>

<=> x = 7

Good luck! :)

3 0
3 years ago
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