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ira [324]
3 years ago
12

Factor 3^5 + 12^4 − 36^3

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

-39501

Step-by-step explanation:

3^5 + 12^4 − 36^3 can be rewritten with 3^3 as a factor showing up one or more times in each term:

(3^3)(3^2) + 3^4*4^4 - (6^2)^3                      or:

(3^3)(3^2) + (3^3)*3*256 - (6^6)                     or:

     same            same     - 3^6*2^6                

Factoring out 3^3, we get:

(3^3)(3^2) + 3*256 - 3^3*64)        or

(3^3){9 + 256 -1728} or

3^3{-1463}, oe

-39501

Crazy boy [7]3 years ago
7 0
Find the greatest common factor among the bases, which is 3. Now find the lowest power that they can all go in to, that’s also 3. So we’re factoring our a 3^3 to get :

3^3[(1^2) + (4^1) + (12)]
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If you save $700 and earn $3 interest for every $100, how much money will you have in all?
Margaret [11]

Answer:

721

Step-by-step explanation

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So you have 7 hundred and 7 times 3 is 21.

700+21=721

4 0
3 years ago
Read 2 more answers
Simplify the function. Than determine the key aspects of the function
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To simplify the function, we need to know some basic identities involving exponents.


1. b^(ax)=(b^x)^a=(b^a)^x

2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)


Now simplify f(x), where

f(x)=(1/3)*(81)^(3*x/4)

=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]

=(1/3)(3^(4*3*x/4) [ rule 1 above ]

=(1/3) (3^(3*x)

=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]



(A) Initial value is the value of the function when x=0, i.e.

initial value

= f(0)

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=(1/3)(3^(3*0))

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=(1/3)(1)

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(B) the simplified base base is 3 (or 27 if the other form is used)


(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).


(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).

8 0
4 years ago
7-8th grade math level
Ne4ueva [31]

Answer: Let me try to figure this out but this is not 7-8 grade math level

Step-by-step explanation:

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