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bonufazy [111]
2 years ago
7

Your friend just recovered from a painful bacterial ear infection. Her first day back at school, she says, "Scientists should ju

st
figure out how to eliminate all the bacteria in the world so that no one gets sick!" What is wrong with this statement? What
would happen if there were no bacteria on earth?
Mathematics
1 answer:
Goryan [66]2 years ago
6 0

Answer:

Earth dies

Step-by-step explanation:

If there were no bacteria on earth everything that lives and breaths will cease to exist, No water, no trees, no birds, no air, no humans. everything will be gone the earth would just be lifeless

You might be interested in
Calculate the product of 8/15, 6/5, and 1/3. 
Mariulka [41]
\frac{8}{15} * \frac{6}{5} * \frac{1}{3}

First, I would multiply the last two fractions because they're smaller and easier to work with:

\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}

Now that we've simplified it, we could multiply these terms and simplify.  An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}

We can now multiply these terms:

\frac{8}{5} * \frac{2}{15} =  \frac{16}{75}

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
5 0
3 years ago
An environmental group conducted a study to determine whether crows in a certain region were ingesting food containing unhealthy
nydimaria [60]

Part A

Given info:

  • xbar = sample mean = 4.90 ppm
  • s = sample standard deviation = 1.12 ppm
  • n = 23 = sample size

Because n > 30 is not true, and we don't know the population standard deviation (sigma), this means we must use a T distribution.

The degrees of freedom here are n-1 = 23-1 = 22.

At 90% confidence and the degrees of freedom mentioned, the t critical value is roughly t = 1.717

Use a T distribution table or calculator to determine this. If you don't have a calculator for the task, then you can search out "inverse T calculator" and there are tons of free options to pick from.

The margin of error E is

E = t*s/sqrt(n)

E = 1.717*1.12/sqrt(23)

E = 0.400982

This is approximate and accurate to 6 decimal places.

The confidence interval is going to be xbar plus or minus that E value

L = lower bound = xbar - E = 4.90 - 0.400982 = 4.499018 = 4.50

U = upper bound = xbar + E = 4.90 + 0.400982 = 5.300982 = 5.30

The confidence interval in the format of (L, U) is (4.50, 5.30)

You could also express it as the format L < mu < U and it would be 4.50 < mu < 5.30; however, I'll stick to the first method.

<h3>Answer:  (4.50, 5.30)</h3>

=====================================================

Part B

Since we know sigma = 2.6 is the population standard deviation, we can use a Z distribution now.

At 90% confidence, the z critical value is roughly 1.645; use a table or calculator to determine this.

n = \left(\frac{z*\sigma}{E}\right)^2\\\\n \approx \left(\frac{1.645*2.6}{0.03}\right)^2\\\\n \approx 20325.254444 \\\\

Round this up to the nearest integer to get 20326. For min sample size problems, <u>always</u> round up.

<h3>Answer: 20326</h3>
6 0
2 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
2 years ago
A fruit sekker buts 50 boxes of mangoes each containing 100 m mangoes at the rate of ₹1200 per box he sells each mangoes for ₹20
Dahasolnce [82]

Answer:

₹40000, 66.6%

Step-by-step explanation:

Given data

Number of boxes= 50

Cost per box= ₹1200

Total cost= 50*1200= ₹60000

Total number of mangoes in all 50 boxes= 50*100= 5000 mangoes

Cost price per mago= 60000/5000=  ₹12

Selling price per mango=  ₹20

profit = selling price- cost price

profit=  20-12

proft=  ₹8

Total profit = 8*5000

Total profit= ₹40000

%profit = 40000/60000*100

%profit= 0.666*100

%profit= 66.6%

8 0
3 years ago
Please help,I really need it
dalvyx [7]
What do you need help with?
5 0
3 years ago
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