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Reptile [31]
3 years ago
6

What is the discriminant of the quadratic equation 0 = 2x2 + 3x – 5? –37 –31 43 49

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0

Answer:

49

Step-by-step explanation:

took the test on edge

alisha [4.7K]3 years ago
3 0

Answer:

D 49 for e2020 just got a 100 on it

Step-by-step explanation:

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Use the tangent identity to
Lunna [17]

Answer:

tan(x)=\frac{44\sqrt{89}}{89}

Step-by-step explanation:

tan is defined as: tan(x)=\frac{opposite}{adjacent}

sin is defined as: sin(x)=\frac{opposite}{hypotenuse}

cos is defined as: cos(x)=\frac{adjacent}{hypotenuse}

We can also define tan as: tan(x)=\frac{sin(x)}{cos(x)}

because plugging in the definitions of sin and cos in we get: tan(x)=\frac{(\frac{opposite}{hypotenuse})}{(\frac{adjacent}{hypotenuse})}\\\\tan(x)=\frac{opposite}{hypotenuse}*\frac{hypotenuse}{adjacent}\\\\tan(x)=\frac{opposite}{adjacent}

which you'll notice is the original definition of tan(x)

So using this definition of tan(x) we can use the givens sin(x) and cos(x) to find tan(x)

sin(x)=\frac{44}{45}\\\\cos(x)=\frac{\sqrt{89}}{45}\\\\tan(x)=\frac{sin(x)}{cos(x)}

plugging in sin(x) and cos(x) we get:

tan(x)=\frac{\frac{44}{45}}{\frac{\sqrt{89}}{45}}\\\\tan(x)=\frac{44}{45}*\frac{45}{\sqrt{89}}\\\\tan(x)=\frac{44}{\sqrt{89}}

We usually don't like square roots in the denominator, and from here we want to rationalize the denominator which we do by removing the square root from the denominator.

We can do this by multiplying the fraction by: \frac{\sqrt{89}}{\sqrt{89}} which doesn't change the value of the fraction since it simplifies to 1, but it gets rid of the square root in the denominator

tan(x)=\frac{44}{\sqrt{89}}*\frac{\sqrt{89}}{\sqrt{89}}\\\\tan(x)=\frac{44\sqrt{89}}{89}

5 0
1 year ago
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