1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Daniel [21]
3 years ago
6

PLZ HELP

Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

61

Step-by-step explanation:

a_{1}=5\\a_{n}=2a_{n-1}+3\\a_{2}=2*5+3=13\\a_{3}=2*13+3=29\\a_{4}=2*29+3=61

You might be interested in
The expression f(x) = 12(1.035)* models the monthly growth of membership in the new drama club at a school. According to the fun
olga nikolaevna [1]

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

y=a(1+r)^{x}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>x</em> = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

f(x) = 12\cdot(1.035)^{x}

Comparing this function with the exponential growth function:

a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}

Then value of <em>r</em> is 0.035 or 3.5%.

Thus, the monthly growth rate is 3.5%.

7 0
3 years ago
Simplify: (3x^3+2x-3)-(4x^3-x^2+x
ad-work [718]

Answer: -x^3 - x^2 + 3x - 3

Glad I could help :D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
A gift company sell carved rectangular signs. The company charges by the área of the sign. A sign has an área of 120 square inch
lorasvet [3.4K]

Answer: 24

Step-by-step explanation:

4 0
3 years ago
Drag and drop the missing values of the relation into the correct boxes to complete the table below.
Zepler [3.9K]

Answer:

1

9

3

4

5 2

Step-by-step explanation:

Just match it with the coordinate points you see above

3 0
3 years ago
Other questions:
  • Rebecca and Tom Payton have decided to buy a home that costs $200,000. The Paytons can put down 20% of the home's price. They ha
    5·1 answer
  • The lengths of the sides of a triangle are in the extended ratio 5 ​: 7 ​: 10. The perimeter of the triangle is 88cm. What are t
    13·2 answers
  • Can I get some help on these
    6·1 answer
  • Consider this function.
    14·2 answers
  • if there are 13 cookies birthday party is there any way to divide them equally amongst a group of friends so that each has a who
    6·1 answer
  • A glass holds 189 milliliters of juice. How many liters will 36 glasses hold?
    11·1 answer
  • 6 is the ______ root of 36​
    9·2 answers
  • The radius of a circle is 4 yards. What is the circle's area? r=4 yd Use 3.14 for ​.
    13·1 answer
  • What is the circumference and area of this circle? (Use 3.14 for pi)
    6·1 answer
  • The first step in solving using the substitution method is.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!