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skad [1K]
3 years ago
13

Heather measures the temperature of her coffee to be 133.4 degrees fahrenheit. It is actually 145 degrees fahrenheit. What is th

e percent error of Heathers calculation?
Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

The percent error of Heather's calculation is <u>8%</u>.

Step-by-step explanation:

Given:

Heather measures the temperature of her coffee to be 133.4 degrees fahrenheit. It is actually 145 degrees fahrenheit.

Now, to find the percent error of Heather's calculation.

The temperature of coffee Heather measures = 133.4° F.

Coffee's actual temperature = 145° F.

So, to get the measurement in error we subtract the temperature of coffee Heather measures from coffee's actual temperature:

145-133.4=11.6\°.

Now, to get the percent error:

\frac{11.6}{145}\times 100

=\frac{1160}{145}

=8\%.

Therefore, the percent error of Heather's calculation is 8%.

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Luke has $21 more than rachel and $48 more than daniel. altogether they have $168. how much does luke have?
Anettt [7]

this can be solve by 3 variable equation

let x be the money of luke

y money of rachel

z money of daniel

first equation

x = y + 21

second equation

x = z + 48

third equation

x + y + z = 168

solving simultaneously

x =79

y = 58

z = 31

<span> </span>

7 0
3 years ago
Edward wants to spend less than $115 to buy a
nikdorinn [45]

Answer: x < 30

Step-by-step explanation:

Let the cost of a jean be x

cost of a shirt = $25

cost of 3 jeans = 3x

since he wants to spend less than $115 , this means that

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7 0
2 years ago
Explain the steps you would take to complete this conversion problem
OLEGan [10]

Answer:

20909.09 grams

Step-by-step explanation:

\frac{46 \: lb}{1}  \times  \frac{1 \: kg}{2.2 \: lb}   \times  \frac{1000 \: g}{1 \: kg}  = \\ \frac{46 \: lb}{2.2 \: lb}  \times  \frac{1 \: kg}{1} \:   \times  \frac{1000 \: g}{1 \: kg}  = \\\frac{230 \: }{11 \:}  \times \frac{1 \: kg}{1 \: kg \:}\times \frac{1000 \: g}{1 \:}  = \\\frac{230 \: }{11 \:}  \times \frac{1}{1}\times \frac{1000 \: g}{1 \:}  = \\\ \frac{230}{11}g  \times 1g  \times \: 1000g

= 230 grams / 11 grams × 1000 grams = 20.90909... × 1000 = 20909.09 grams

8 0
2 years ago
Read 2 more answers
What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

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5 0
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I would have to say 85 but thats just a guess.
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