(2^6)^x=1
(4)^x=1
(4)^0=1
1=1
X=0
(5^0)^x=1
(1)^x=1
x=(-∞,∞)
B = 2A/h
The way you would get this is first by clearing the fraction. So in order to clear the fraction, you have to multiply the equation by the denominator.
2(A = 1/2bh)
2A = 1bh
2A = bh
Then you have to isolate the variable. So you'd divide bh by h in order to get b by itself. So you'd end up with:
2A/h = bh/h
2A/h = b
Honestly I don’t really know but I do believe the answers to
