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4 years ago

Write a division problem whose quotient has its first digit in the hundreds place

1 answer:

7 0

Quotient is another name for the answer to a division problem
the hundreds place is the 3rd number before the decimal, 9999999.0 ^this one
so you need to find a division problem that equals something between 100 and 999
1000 divided by 10 is a good one, the answer to that problem is 100, and 100 has its first digit in the hundreds place.

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Determine the point estimate of the population mean and margin of error for the confidence interval.Lower bound is 22, upper bou

irakobra [83]

Answer: The point estimate of the population mean is <u>25</u>.

The margin of error for the confidence interval is <u>3</u> .

Step-by-step explanation:

The confidence interval for population mean is given by :-

$(\overline{x}-E , \overline{x}+E)$ , here $\overline{x}$ is the point estimate of the population mean and E is the margin of error .

As per given , we have

Lower bound of CI = $\overline{x}-E =22$ (1)

Upper bound of CI = $\overline{x}+E =28$ (2)

Add (1) and (2) , we get

$2\overline{x}=50\\\Rightarrow\ \overline{x}=25$

Subtract (1) from (2) , we get

$2E=6\\\Rightarrow\ E=3$

Hence, the point estimate of the population mean is <u>25</u>.

The margin of error for the confidence interval is <u>3</u> .

6 0

3 years ago

Read 2 more answers

Hey guys! Can you help me how to solve number 16, 18, and 20. Because I don’t understand how to solve this

maria [59]

Problem 16

<h3>Answer: i</h3>

------------------

Work Shown:

The exponent 41 divided by 4 leads to

41/4 = 10 remainder 1

The "remainder 1" means that

i^(41) = i^1 = i

The reason why I divided by 4 is because the pattern shown below

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

repeats itself over and over. So this is a block of four items repeated forever.

=====================================

Problem 18

<h3>Answer: 1</h3>

------------------

Work Shown:

Divide 3136 over 4 to get

3136/4 = 784 remainder 0

Therefore,

i^3136 = i^0 = 1

=====================================

Problem 20

<h3>Answer: i</h3>

------------------

Work Shown:

Combine i^6*i^7 into i^13. We add the exponents here

Now divide by 4 to find the remainder

13/4 = 3 remainder 1

So, i^13 = i^1 = i

3 0

3 years ago

Can someone solve for x please:

Alecsey [184]

THe LCD is x(x^2 - 4)

so multiplying through by this we get:-

2x(x + 2) + 7x = 5(x^2 - 4)
2x^2 + 4x + 7x = 5x^2 - 20
3x^2 - 11x - 20 = 0

(3x + 4)(x - 5 ) = 0

so x = 5 , -4/3

Its the second choice

3 0

3 years ago

Read 2 more answers

Determine the solution to the equation.

postnew [5]

Answer : x = 25

5 x=32−7
5 x = 25
25x = 625
x=625/25
x=25

good luckkk

8 0

3 years ago

Please help me hurry please

aalyn [17]

Answer:

y = root under 24 (evaluate it if necessary)

or y = 2 root 6

Step-by-step explanation:

Let the reference angle be x

for the triangle in left,

b = 6-4 = 2

Now,

taking x as refrence angle,

cosx = b/h

or, cosx = 2/h

again,

for the bigger triangle,

taking x as reference angle,

cosx = b/h

or, cosx = b/6

As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,

Let's suppose its a

so, cosx = a/6 = 2/a

now,

a/6 = 2/a

or, a² = 12

now,

for bigger triangle, using pythagoras theorem,

h² = p²+b²

or, 6² = y² + a²

or, 36 = y² + 12

or, y² = 24

so, y = root under 24

5 0

2 years ago