Hi!
Shawna is correct because since it's multiplied to the 5-n you have to do the opposite which is division.
Dexter is also correct because after distributing you can continue solving, there is nothing wrong with that.
Hope this helps!
Answer:
x = 23
y = 7
z = 11
Step-by-step explanation:
Since ∆PRS ≅ ∆CFH, therefore,
m<R = m<F
13y - 1 = 90° (substitution)
Add 1 to both sides
13y - 1 + 1 = 90 + 1
13y = 91
Divide both sides by 13
13y/13 = 91/13
y = 7
Since ∆PRS ≅ ∆CFH, therefore,
PS = CH
2x - 7 = 39 (substitution)
Add 7 to both sides
2x - 7 + 7 = 39 + 7
2x = 46
Divide both sides by 2
2x/2 = 46/2
x = 23
Since ∆PRS ≅ ∆CFH, therefore,
m<S = m<H
Find m<S
m<S = 180 - (m<P + m<R) (sum of ∆)
m<S = 180 - (28 + (13y - 1)) (substitution)
Plug in the value of y
m<S = 180 - (28 + (13)(7) - 1))
m<S = 180 - (28 + 91 - 1)
m<S = 180 - 118
m<S = 62°
Therefore, since m<S = m<H,
62° = 6z - 4 (substitution)
Add 4 to both sides
62 + 4 = 6z - 4 + 4
66 = 6z
Divide both sides by 6
66/6 = 6z/6
11 = z
Answer:
100% sure your answer is 55, there was 55 questions on the test.
Answer:
y =
x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (- 4, - 4)
m =
=
, thus
y =
x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 6, - 5), then
- 5 = - 3 + c ⇒ c = - 5 + 3 = - 2
y =
x - 2 ← equation of line
Answer:
602.50 hours
Step-by-step explanation:
Given that a manufacturing plant uses light bulbs whose life spans are normally distributed, with mean and standard deviation equal to 500 and 50 hours,
It was decided to replace the bulbs so that no more than 2% of the bulbs to burn out between replacement periods
i.e. we have to construct 98% confidence interval right tailed to get this.
Z value is 2.05 for this (Upper tailed 0.98 probability)
Hence margin of error ![= 2.05 (std dev)\\=2.05(50)\\= 102.50](https://tex.z-dn.net/?f=%3D%202.05%20%28std%20dev%29%5C%5C%3D2.05%2850%29%5C%5C%3D%20102.50)
The upper bound for this would be
![500+102.50 =602.50](https://tex.z-dn.net/?f=500%2B102.50%20%3D602.50)
So to keep below 2% the bulbs to burn out it should be replaced before 602.50 hours.