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almond37 [142]
3 years ago
10

Choose the definition for the function

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

In mathematics, a function is a binary relation over two sets that associates to every element of the first set exactly one element of the second set. Typical examples are functions from integers to integers or from the real numbers to real numbers.

Step-by-step explanation:

hope this helps you :)

eimsori [14]3 years ago
7 0
I hope this helps!!!!!

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-(1+7x)=6(-7-x)+36 <br> Alg 2
olganol [36]

Let's solve your equation step-by-step.

−(1+7x)=6(−7−x)+36

Step 1: Simplify both sides of the equation.

−(1+7x)=6(−7−x)+36

−7x+−1=(6)(−7)+(6)(−x)+36(Distribute)

−7x+−1=−42+−6x+36

−7x−1=(−6x)+(−42+36)(Combine Like Terms)

−7x−1=−6x+−6

−7x−1=−6x−6

Step 2: Add 6x to both sides.

−7x−1+6x=−6x−6+6x

−x−1=−6

Step 3: Add 1 to both sides.

−x−1+1=−6+1

−x=−5

Step 4: Divide both sides by -1.

−x

−1

=

−5

−1

x=5

Answer:

x=5

7 0
3 years ago
(- 6x + 7) + (2x - 6) = - 4x + 1
inna [77]

Answer:

Step-by-step explanation:

-4x + 1 = -4x + 1

1 = 1

infinitely many solutions

7 0
3 years ago
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
Hello can you please help me posted picture of question
astra-53 [7]
The answer is D because there is one of the 0 and one of the 9
7 0
3 years ago
Read 2 more answers
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