Let's assume
boiling point is y
altitude is x
we are given
This relationship between altitude and boiling point is linear
At an altitude of 1000 feet, water boils at 210°F
so, first point is (1000,210)
so, x1=1000 , y1=210
At an altitude of 3000 feet, water boils at 206°F
so, second point is (3000,206)
so, x2=3000,y2=206
now, we can find slope

now, we can plug values


now, we can use point slope form of line

so, we can plug it

so, point slope form of line is

now, we can plug x=8000
and then we can solve for y


So,
the boiling point of water at an altitude of 8000 feet is 196°F..........Answer
Answer:
x=8
Step-by-step explanation:
I think you mean find x, not m.
since angle DEG and angle GEF are a linear pair, they equal 180º.
18x-9 + 4x+13 = 180
22x + 4 = 180
subtract 4 from each side
22x = 176
divide each side by 22
x=8
23400 x 8/100 = 1872 = the loss
1872 : 12 = 156= the loss each month
156/1872*100% = 8,33 % then round it
Answer:
answer is B 38-18
Step-by-step explanation:
38 + (-18)
38-18