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bulgar [2K]
3 years ago
14

The mean of eight numbers is 40 and the mean of other twelve different numbers is 30. What is the mean of all the twenty numbers

?
​
Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:  34

================================================

Work Shown:

S = sum of the first 8 numbers

S/8 = 40 is the mean of those first 8 numbers

S = 8*40

S = 320 so the first 8 numbers add to this value

-------

R = sum of the 12 remaining values

R/12 = 30

R = 12*30

R = 360 is what the other 12 values add to

-------

R+S = 360+320 = 680  is what all twenty values add to. Divide this by 20 to get the overall average

(R+S)/20 = 680/20 = 34

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In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

                                                                     are congruent

9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

4 0
3 years ago
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