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Alina [70]
3 years ago
7

Can someone please HELP!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0
The equation that should be used is T = 16p, where T = the amount to make and p = the amount of people. 

We know this because she expects each person who comes to the party to drink 2 8-ounce glasses. When we multiply we know that each person will drink 16 ounces total. We can then determine that we can multiply people by 16 and get the total ounces. 
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help plz The total cost of a shirt and a jacket was $99.34. If the price of the shirt was $7.76 less than the jacket, what was t
GalinKa [24]

Answer: Shirt costs $45.79

Step-by-step explanation:

jacket- x

shirt (x-7.76)

x+x-7.76=99.34

2x - 7.76 = 99.34

2x = 107.10

x=53.55

Jacket costs 53.55 and Shirt costs 53.55-7.76= 45.79

6 0
3 years ago
Solve for x: 4 − (x + 2) < −3(x + 4)
jeyben [28]
4 - (x+2) < -3(x+4)

4 -1(x) -1(2) < -3(x) -3(4)
4 - x - 2 < -3x -12
 <u>  +3x        +3x      </u>
<u />2 + 2x    <   -12
<u>-2                   -2    
</u>      2x     < -14
<u /> <u>     ÷2          ÷2    </u>
        x      < -7

assume that x = -8

4 - (-8 + 2) < -3(-8 + 4)
4 - (-6) < -3(-4)
4 + 6 < 12
10 < 12  the inequality is true.
8 0
3 years ago
According to a survey of 500, the mean income before taxes of consumer units (i.e., households) inthe U.S. was $60,533 with a st
ioda

Answer:

The margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

Step-by-step explanation:

We are given that according to a survey of 500, the mean income before taxes of consumer units (i.e., households) in the U.S. was $60,533 with a standard error of 717.51.

Margin of error tells us that how much our sample mean value deviates from the true population value.

<u></u>

<u>Margin of error is calculated using the following formula;</u>

        Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

where, \alpha = level of significance = 1 - confidence level

                                                    = 1 - 0.95 = 0.05 or 5%

Standard of Error =  \frac{\sigma}{\sqrt{n} } = 717.51

Now, the value of z at 2.5% level of significance (\frac{0.05}{2} =0.025) is given in the z table as 1.96, that means;

            Margin of error =  Z_(_\frac{\alpha}{2}_) \times \text{Standard of Error}

                                      =  1.96 \times 717.51 = 1406.32

Hence, the margin of error for constructing a 95% confidence interval on the population mean income before taxes of all consumer units in the U.S is 1406.32.

3 0
4 years ago
Helppp!!!!!!!!!!!! Stuck
babymother [125]

Answer:

i dont know dude

Step-by-step explanation:

5 0
3 years ago
The man who put soap in his soup so he could wash _ down with something
amm1812
So the man can wash lies Down
5 0
3 years ago
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