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Sophie [7]
3 years ago
11

What is the equation of the line in slope intercept form?

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

y=x-4

Step-by-step explanation:

Andru [333]3 years ago
8 0

Answer:

y = x - 4

Step-by-step explanation:

Slope (M) = 1

Y intercept (b) = -4

~theLocoCoco

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Find the value of x.
wlad13 [49]

Answer: The letter x is often used in algebra to mean a value that is not yet known. it is called a variable or somethings an unknown in x + 2 = 7, x is a variable but we can work out its value if you try a variable does not have to be x though it could be y or w, or any letter, name or symbol. See: variable

Step-by-step explanation: and that's it! have a yummy cookie day! ◑﹏◐

3 0
3 years ago
Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

⇒ a_n=a +(n-1)d

⇒ -450=46 +(n-1)(-4)

⇒ -496=(n-1)(-4)

⇒ \frac{-496}{-4}=n-1

⇒ 124=n-1

⇒ n=125

Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

⇒ S_1_2_5 = \frac{125}{2}(-404)

⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0
3 years ago
Read 2 more answers
Help i’m begging plsss
olga_2 [115]

Answer:

x=8

Step-by-step explanation:

Given

AB||CD

\angle ABC = 5x + 50

\angle BCD = 7x + 34

Required

Find x

If AB||CD i.e. If AB is parallel to CD, then

\angle ABC = \angle BCD

Substitute values for ABC and BCD

5x + 50 = 7x + 34

Collect Like Terms

5x - 7x = -50 + 34

-2x = -16

Multiply through by -\frac{1}{2}

-\frac{1}{2} * -2x = -16 * -\frac{1}{2}

\frac{1}{2} * 2x = 16 * \frac{1}{2}

\frac{2x}{2} = \frac{16}{2}

x = \frac{16}{2}

x=8

3 0
3 years ago
A mountain railway AB is of length 864m and rises at an angle of 120° to the horizontal.
Ainat [17]

Answer:

The height above sea level at <em>B</em> is approximately 1,604.25 m

Step-by-step explanation:

The given length of the mountain railway, AB = 864 m

The angle at which the railway rises to the horizontal, θ = 120°

The elevation of the train above sea level at <em>A</em>, h₁ = 856 m

The height above sea level of the train when it reaches <em>B</em>, h₂, is found as follows;

Change in height across the railway, Δh = AB × sin(θ)

∴ Δh = 864 m × sin(120°) ≈ 748.25 m

Δh = h₂ - h₁

h₂ = Δh + h₁

∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m

The height above sea level of the train when it reaches <em>B</em> ≈ 1,604.25 m

4 0
3 years ago
A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
3 years ago
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