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3 years ago

What is the equation of the line in slope intercept form?

Mathematics

2 answers:

poizon [28]3 years ago

8 0

Answer:

y=x-4

Step-by-step explanation:

Andru [333]3 years ago

8 0

Answer:

y = x - 4

Step-by-step explanation:

Slope (M) = 1

Y intercept (b) = -4

~theLocoCoco

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Find the value of x.

wlad13 [49]

Answer: The letter x is often used in algebra to mean a value that is not yet known. it is called a variable or somethings an unknown in x + 2 = 7, x is a variable but we can work out its value if you try a variable does not have to be x though it could be y or w, or any letter, name or symbol. See: variable

Step-by-step explanation: and that's it! have a yummy cookie day! ◑﹏◐

3 0

3 years ago

Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)

JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

Step-by-step explanation:

We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

$a=46\\d=42-46=-4$

So , Let's calculate how many terms are there as :

⇒ $a_n=a +(n-1)d$

⇒ $-450=46 +(n-1)(-4)$

⇒ $-496=(n-1)(-4)$

⇒ $\frac{-496}{-4}=n-1$

⇒ $124=n-1$

⇒ $n=125$

Sum of an AP is :

⇒ $S_n = \frac{n}{2}(2a+(n-1)d)$

⇒ $S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))$

⇒ $S_1_2_5 = \frac{125}{2}(-404)$

⇒ $S_1_2_5 =-25,250$

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0

3 years ago

Read 2 more answers

Help i’m begging plsss

olga_2 [115]

Answer:

$x=8$

Step-by-step explanation:

Given

$AB||CD$

$\angle ABC = 5x + 50$

$\angle BCD = 7x + 34$

Required

Find x

If $AB||CD$ i.e. If AB is parallel to CD, then

$\angle ABC = \angle BCD$

Substitute values for ABC and BCD

$5x + 50 = 7x + 34$

Collect Like Terms

$5x - 7x = -50 + 34$

$-2x = -16$

Multiply through by $-\frac{1}{2}$

$-\frac{1}{2} * -2x = -16 * -\frac{1}{2}$

$\frac{1}{2} * 2x = 16 * \frac{1}{2}$

$\frac{2x}{2} = \frac{16}{2}$

$x = \frac{16}{2}$

$x=8$

3 0

3 years ago

A mountain railway AB is of length 864m and rises at an angle of 120° to the horizontal.

Ainat [17]

Answer:

The height above sea level at B is approximately 1,604.25 m

Step-by-step explanation:

The given length of the mountain railway, AB = 864 m

The angle at which the railway rises to the horizontal, θ = 120°

The elevation of the train above sea level at A, h₁ = 856 m

The height above sea level of the train when it reaches B, h₂, is found as follows;

Change in height across the railway, Δh = AB × sin(θ)

∴ Δh = 864 m × sin(120°) ≈ 748.25 m

Δh = h₂ - h₁

h₂ = Δh + h₁

∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m

The height above sea level of the train when it reaches B ≈ 1,604.25 m

4 0

3 years ago

A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

8 0

3 years ago