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2 years ago

How do I solve x(3x-2)=(3x+1)(x-2)?

Mathematics

2 answers:

vampirchik [111]2 years ago

5 0

First you simplify and combine like terms. Then you subtract 4x from both sides, leaving you with -2x = -1. Divide both by -2x, giving you the final of x = 1/2!!!

docker41 [41]2 years ago

4 0

x(3x - 2) = (3x + 1)(x - 2)

3x^2 - 2x = 3x^2 - 6x + x - 2

3x^2 - 2x = 3x^2 - 5x - 2

-2x = -5x - 2

-2x + 5x = -2

3x = -2

x = -2/3

hope this helped xx

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$\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}$

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$\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512$

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