How do I solve x(3x-2)=(3x+1)(x-2)?
2 answers:
You might be interested in
Answer:
<em>95% of confidence interval for the Population</em>
<em>( 6.1386 , 6.8614)</em>
Step-by-step explanation:
<u><em>Step( i ):-</em></u>
<em>Given random sample size 'n' =85</em>
<em>Mean of the sample size x⁻ = 6.5 years</em>
<em>Standard deviation of Population = 1.7 years</em>
<em>Level of significance = 0.95 or 0.05</em>
<u><em>Step(ii):-</em></u>
<em>95% of confidence interval for the Population is determined by</em>
<em></em><em></em>
<em></em><em></em>
<em>( 6.5 - 0.3614 , 6.5 + 0.3614 )</em>
<em>( 6.1386 , 6.8614)</em>
<u><em>Conclusion</em></u><em>:-</em>
<em>95% of confidence interval for the Population</em>
<em>( 6.1386 , 6.8614)</em>
Answer:
y+11=-(x-4)
Step-by-step explanation:
since the equation is perpendicular to y=4x-2, m=-1/4 (negative reciprocal). (x_1,y_1)=(4,-11), plug all the values into the equation y- y_1 = m(x-x_1) and we get y+11=-(x-4)