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3 years ago

6

I hope the way the problems written is understandable. 4a^3b-8a^2b^2+2ab^3 ,I need to find the GCF for this problem and like ASA

P if possible please.

1 answer:

olga2289 [7]3 years ago

7 0

Answer:Greatest common factor is 2 it seems but i see tetration

dividing by 2 for each coefficient is complex if you have secondary variables inpower is this a typo

4(aaa)^b-8(aa)^b

Step-by-step explanation:

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If f ( x ) = x 4 + 6 , g ( x ) = x − 5 and h ( x ) = √ x , then f ( g ( h ( x ) ) ) =

zaharov [31]

Answer:

fgh(x)=4 $\sqrt{x}$ -14

Step-by-step explanation:

when solving composite fuctions we go from the right to the left

meaning we replace the x in the g function with the entire h function

then replace the x in the f function with the entire new g function

h(x)= $\sqrt{x}$

g( $\sqrt{x}$ )= $\sqrt{x}$ -5

f( $\sqrt{x}$ -5)=4( $\sqrt{x}$ -5)+6

f( $\sqrt{x}$ -5)=4 $\sqrt{x}$ -20+6

fgh(x)=4 $\sqrt{x}$ -14

3 0

2 years ago

Using the order of operations , solve the value of the expression.

velikii [3]

Hello.

$\frac{1}{6} (\sqrt{36} \div 3^{-2}) + 4^{3} \div |-8| = \\ \\ \frac{1}{6} (6 \div \frac{1}{9}) + 64 \div 8 \\ \\ \frac{1}{6} \times 54 + 8 \\ \\ \frac{54}{6} + 8 \\ \\ 9 + 8 = \\ \\ 17$

Hope I helped!

8 0

3 years ago

Divide and round to the nearest tenth 3.5 divided by 2.29

Jlenok [28]

1.53 is your answer
Hope this helps!

3 0

3 years ago

A plane is a figure. The intersection of two planes that do not coincide (if it exists) is a .

Elan Coil [88]

Two planes may intersect, be parallel, or coincide .

If two planes intersect, then the set of common points is a line that lies in both planes. Two parallel planes can not intersect.

The intersection of two planes that do not coincide (if it exists) is always a line.

If an intersection of the planes does not exist, the planes are said to be parallel.

4 0

3 years ago

Read 2 more answers

Find the equation of the line that passes through the points (12,21) and (46,33). V.35r-162

AnnZ [28]

Answer:

the answer is Y=(6/17)X + (285/17)

Step-by-step explanation:

1. Identify the X and Y coordinate of each point.

for example, the first point could be (12,21), therefore X1 = 12 and Y1 = 21 and the second point is then (46,33), therefore X2 = 46 and Y2 = 33

2. to find the equation of the line it is necessary to find the slope.

knowing that the equiation of the slope is M = Y2-Y1/X2-X1 we replace

$m=\frac{33-21}{46-12}=\frac{12}{34}$ and then we simplify the result to $\frac{12}{34}$

3. Using the Point-slope equation which is Y-Y1=M(X-X1) we replace

$Y-33=\frac{6}{17}(X-46)$

$Y=\frac{6}{17}X-\frac{276}{17}+33$

$Y=\frac{6}{17}X+\frac{285}{17}$

7 0

3 years ago