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Levart [38]
3 years ago
6

I hope the way the problems written is understandable. 4a^3b-8a^2b^2+2ab^3 ,I need to find the GCF for this problem and like ASA

P if possible please.
Mathematics
1 answer:
olga2289 [7]3 years ago
7 0

Answer:Greatest common factor is 2 it seems but i see tetration

dividing by 2 for each coefficient is complex if you have secondary variables inpower is this a typo

4(aaa)^b-8(aa)^b

Step-by-step explanation:

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Can someone please help me out with my grades are bad
dolphi86 [110]

Answer:

Step-by-step explanation:

In a dilatation for find the new coordinates we have to multiply the initial value for the the scale factor

A’(-3, 12)

B’(9,6)

C’(-9,-3)

so the general rule is:

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7 0
3 years ago
Rewrite 3x+5y=11 and -5x+7y=9 in slope intercept form
chubhunter [2.5K]

Problem 1

subtract 3 x

5y=-3x+11

divide 5

y=3/5x+2.2'

Problem 2

add 5x

7y=5x+9

divide 7

y=5/7x+1.3'

'notice'

you can put 2.2 into a fraction (11/5) and 1.3 (9/7) if your teacher allows it, but i put them into decimals

4 0
3 years ago
Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d
Alexxx [7]

Answer:

\chi^2 =\frac{35-1}{9} 2.12^2 =16.979

p_v =P(\chi^2

If we compare the p value and the significance level provided we see that p_v so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=35 represent the sample size

\alpha=0.01 represent the confidence level  

s =2.12 represent the sample deviation obtained

\sigma_0 =3 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 9

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{35-1}{9} 2.12^2 =16.979

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0
3 years ago
Marla filled up her car's gas tank and then went on a trip. After she drove 329 miles, she filled her tank with 14 gallons of ga
romanna [79]

Answer:

23 1/2 miles per gallon

Step-by-step explanation:

We start with dividing 329 miles with 14 gallons because it asks to find the number of miles on each gallon of gas -

          Miles

-----------------------------     =

Each gallon of gas

329 ÷ 14 = 23 1/2 miles per gallon

6 0
3 years ago
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