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agasfer [191]
3 years ago
5

Ardit has 8 chapters of a book left to read. He reads 2/3 of a chapter each day. How many days does it take to finish reading th

e book
Mathematics
1 answer:
abruzzese [7]3 years ago
6 0
3days=3chapters so he would have to read for 8 days
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What is the ratio 15 girls to 6 boys in simplest form?
Alenkinab [10]
5 girls to 2 boys, it’s not asking for boys and girls
4 0
3 years ago
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If 3(d+1)=4(d–2)<br> then what is the value of 5(d–2)
Sonja [21]

Answer:

5(d - 2) = 45

Step-by-step explanation:

Solve the given equation for d

3(d + 1) = 4(d - 2) ← distribute parenthesis on both sides

3d + 3 = 4d - 8 ( subtract 3d from both sides )

3 = d - 8 ( add 8 to both sides )

11 = d

Then

5(d - 2) = 5(11 - 2) = 5(9) = 45

3 0
2 years ago
Which of the following best describes perpendicular lines
Usimov [2.4K]

Answer:

B.

Step-by-step explanation:

Perpendicular lines always intercept at a right angle (90 degrees).

8 0
3 years ago
Read 2 more answers
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Asssesmenttt lasttt......
ratelena [41]

Answer:

<em>( About ) 1.77 seconds; Option B</em>

Step-by-step explanation:

We are given the equation h ( t ) = - 16t^2 + 50, so in order to determine the time let us determine the x - intercept for y ⇒ 0;

- 16t^2 + 50 = 0,

- 16t^2 = - 50,

t^2 = 25 / 8,

Thus t ⇒ √ ( 25 / 8 ), and t ⇒ - √ ( 25 / 8 ),

t ⇒ ( 5√2 )/ 4, and - ( 5√2 )/ 4,

But time is represented only by a positive value, thus

t ⇒ ( 5√2 )/ 4 = 1.767766953......., ( About ) 1.77 seconds

<em>Answer; ( About ) 1.77 seconds; Option B</em>

7 0
3 years ago
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