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yuradex [85]
3 years ago
8

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g –

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0
F(x) = 4 - x^2
g(x) = 6x
(g - f)(x) = g(x) - f(x) = 6x - (4 - x^2) = 6x - 4 + x^2
(g - f)(3) = 6(3) - 4 + 3^2
Artist 52 [7]3 years ago
4 0

Answer:

Option (c) is correct.

(g-f)(3)=6(3)-4+(3)^2

Step-by-step explanation:

Given : f(x)=4-x^2\\\\ g(x)=6x

We have to find the expression is equivalent to (g –f)(3)

That is g(3) - f(3)

First find g(x) - f(x)

We have,

g(x)-f(x)=6x-(4-x^2)\\\\ g(x)-f(x)=6x-4+x^2

Now, put x = 3

We have,

g(3)-f(3)=6(3)-4+(3)^2

Thus, (g-f)(3)=6(3)-4+(3)^2

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Answer: \frac{13}{24}

Step-by-step explanation: 11/12 - 3/8

1. First, we will find a common denomenator. It needs to be the least common factor, or the answer will not be in its simplist form. Let's take a look at the multiples of 12 and 8.

12: 12, 24, 36, 48, 60, 72, 84, 96

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2. Next, we will choose the smallest common multiple. That would be 24.

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11/12 = 22/24

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4. Subtract.

22/24 - 9/24

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Hope this answer helped!

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