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3 years ago

Solve the following system of equations algebraically and check. y=x^2+3x+4 y-x=7

1 answer:

5 0

Y=x^2+3x+4
y-x=7

x^2+3x+4-x=7
x^2+2x+4=7
(factor) x^2+2x-3=0
(x+3)(x-1)=0
X= -3 and X=1
(Plug x in for y)
Y= 1^2+3(1)+4
Y=8
(Check your answer on the second equation)
8-1=7
7=7 (Which is the solution)

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Option A

The solution is $(0, \frac{-1}{4})$

Solution:

Given system of equations are:

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

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We can use substitution method

From eqn 2,

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A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su

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Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

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We can find that the rectangle also will be symmetrical about y axis.

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3 years ago

The function, p(d)equals=1plus+startfraction d over 33 endfraction d 33, gives the pressure, in atmospheres (atm), at a dep

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Answer:

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Step-by-step explanation:

we are given equation as

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