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astraxan [27]
3 years ago
8

Solve the following system of equations algebraically and check. y=x^2+3x+4 y-x=7

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0
Y=x^2+3x+4
y-x=7

x^2+3x+4-x=7
x^2+2x+4=7
(factor) x^2+2x-3=0
(x+3)(x-1)=0
X= -3 and X=1
(Plug x in for y)
Y= 1^2+3(1)+4
Y=8
(Check your answer on the second equation)
8-1=7
7=7 (Which is the solution)
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For the equation y= x + 5, find the value of y when
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Answer:

a) 3 b) 5 c) 7 d) 9

Step-by-step explanation:

For this, you want to replace x in the equation y=x+5 with each of the values listed.

For the first one, -2, the equation becomes y=-2+5, which is solved to y=3.

For the second one, 0, the equation becomes y=0+5, which is solved to y=5.

For the third one, 2, the equation becomes y=2+5, which is solved to y=7.

For the last one, 4, the equation becomes y=4+5, which is solved to y=9.

**This content involves solving algebraic equations with a known variable, which you may wish to revise. I'm always happy to help!

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3 years ago
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rusak2 [61]
1. The answer is two because if you factor what you can from the equation and then simplify, you are left with 2v+16=(v+8)(?), and by looking at it, the correct answer is two, or A. Review your work, make sure to check your answers before submitting
2. Since two simple factors of 8 are 4 and 2, and they add up to 6, the correct answer is (x+4)(x+2), or B
3. Again, two simple factors of 12 are -4 and -3, so the correct answer is (x-3)(x-4), or D
4. Basically, just factor the quadratic trinomial g^2-2g-24, which turns out to (G+4)(g-6), which is B
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