3 years ago

Solve the following system of equations algebraically and check. y=x^2+3x+4 y-x=7

1 answer:

5 0

Y=x^2+3x+4
y-x=7

x^2+3x+4-x=7
x^2+2x+4=7
(factor) x^2+2x-3=0
(x+3)(x-1)=0
X= -3 and X=1
(Plug x in for y)
Y= 1^2+3(1)+4
Y=8
(Check your answer on the second equation)
8-1=7
7=7 (Which is the solution)

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frosja888 [35]

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Gala2k [10]

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