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RideAnS [48]
3 years ago
8

What is 0.8333 forever in a fraction

Mathematics
2 answers:
blondinia [14]3 years ago
8 0

x=0.8\overline{3}\\ 10x=8.\overline{3}\\ 100x=83.\overline{3}\\\\ 100x-10x=83.\overline{3}-8.\overline{3}\\ 90x=75\\ x=\dfrac{75}{90}=\dfrac{5}{6}

Nady [450]3 years ago
7 0

There are a couple of different approaches you can use for this. Here's one.

1. Determine how many digits repeat. (There is just one repeating digit.)

2. Call your number x. Multiply x by 10 to the power of the number of digits found in step 1.

x = 0.8\overline{3}\\10^{1}x=8.3\overline{3}

3. Subtract the original number, then solve for x.

10x-x=9x=8.3\overline{3}-0.8\overline{3}=7.5\\\\x=\dfrac{7.5}{9}=\dfrac{5}{6}

_____

If you recognize that 0.333... (repeating) is 1/3, then you know that 0.0333... (repeating) is 1/10×1/3 = 1/30. Add that to 0.8 = 4/5 and you get

... 4/5 + 1/30 = 24/30 + 1/30 = 25/30 = 5/6

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<h2>Answer:</h2>

Option: A is the correct answer.

A.  negative 5 over 8 minus negative 2 over 8 = negative 3 over 8; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units.

<h2>Step-by-step explanation:</h2>

The location of Point A is : A(-5/8)

and Point B is located at : B(-2/8)

We know that when two points lie over a number line then the distance between the two points is the absolute difference between the two points.

If A is located at a.

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Hence, here the distance between A and B is given by:

|\dfrac{-5}{8}-(\dfrac{-2}{8})|=|\dfrac{-5}{8}+\dfrac{2}{8}|=|\dfrac{-3}{8}|=\dfrac{3}{8}\\\\i.e.\\\\\text{Distance between A and B is}=\dfrac{3}{8}\ \text{units}

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I hope this helps.

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