1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ale4655 [162]
2 years ago
15

PLEASE HELP!! WILL MARK BRAINLIEST FOR CORRECT ANSWER!!!

Mathematics
1 answer:
slega [8]2 years ago
8 0

Answer:

Option 2, 3, 4

Step-by-step explanation:

It cannot be the 1st option because a linear function doesn't have an x^{2} and adding an x to an x will not make it squared. ax + by = c is the linear equation.

It can be the 2nd option because the quadratic formula is  f(x) = ax^{2} + bx + c and the middle portion could cancel when adding 2 together.

It can be option 3, because f(x) = ax^{2} + bx + c plus ax + by = c could give you the resulting function f(x) = -3x^{2} +5

It can be option 4 because multiplying ax + by = c by ax + by = c would give you an x^{2}.

It cannot be option 5 because ax^{2} + bx + c multiplied by ax^{2} + bx + c would give you a function with x^{4}

You might be interested in
40 Points please help
insens350 [35]

Answer:

Slope = ⅓ Y-intercept = -2

Step-by-step explanation:

by transforming the equation to y= ⅓x -2

then it becomes Y= ⅓x +(-2)

then you should get m= ⅓ and b = -2

5 0
2 years ago
Read 2 more answers
What is greater than 1 cup
77julia77 [94]
2 cups your welcome
5 0
3 years ago
Solve for c.<br><br> 2(c +1) = 10
coldgirl [10]

Answer:

c=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(c+1)=10

(2)(c)+(2)(1)=10(Distribute)

2c+2=10

Step 2: Subtract 2 from both sides.

2c+2−2=10−2

2c=8

Step 3: Divide both sides by 2.

2c

2 = 8

2

c=4

8 0
3 years ago
Read 2 more answers
Solve for x. <br>0.71= 1/2(9.8) x^2. ​
Fudgin [204]

Answer: 0.38065

in simpler terms x=±  0.145  =±0.38065

Step-by-step explanation: -490x2+71 = 0  

Subtract  71  from both sides of the equation :  

                     -490x2 = -71

Multiply both sides of the equation by (-1) :  490x2 = 71

Divide both sides of the equation by 490:

                    x2 = 71/490 = 0.145

 

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     x  =  ± √ 71/490  

The equation has two real solutions  

These solutions are  x = ±√ 0.145 = ± 0.38065  

5 0
2 years ago
. (0.5 point) We simulate the operations of a call center that opens from 8am to 6pm for 20 days. The daily average call waiting
SashulF [63]

Answer:

The 95% t-confidence interval for the difference in mean is approximately (-2.61, 1.16), therefore, there is not enough statistical evidence to show that there is a change in waiting time, therefore;

The change in the call waiting time is not statistically significant

Step-by-step explanation:

The given call waiting times are;

24.16, 20.17, 14.60, 19.79, 20.02, 14.60, 21.84, 21.45, 16.23, 19.60, 17.64, 16.53, 17.93, 22.81, 18.05, 16.36, 15.16, 19.24, 18.84, 20.77

19.81, 18.39, 24.34, 22.63, 20.20, 23.35, 16.21, 21.73, 17.18, 18.98, 19.35, 18.41, 20.57, 13.00, 17.25, 21.32, 23.29, 22.09, 12.88, 19.27

From the data we have;

The mean waiting time before the downsize, \overline x_1 = 18.7895

The mean waiting time before the downsize, s₁ = 2.705152

The sample size for the before the downsize, n₁ = 20

The mean waiting time after the downsize, \overline x_2 = 19.5125

The mean waiting time after the downsize, s₂ = 3.155945

The sample size for the after the downsize, n₂ = 20

The degrees of freedom, df = n₁ + n₂ - 2 = 20 + 20  - 2 = 38

df = 38

At 95% significance level, using a graphing calculator, we have; t_{\alpha /2} = ±2.026192

The t-confidence interval is given as follows;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

Therefore;

\left (18.7895- 19.5152 \right )\pm 2.026192 \times \sqrt{\dfrac{2.705152^{2}}{20}+\dfrac{3.155945^2}{20}}

(18.7895 - 19.5125) - 2.026192*(2.705152²/20 + 3.155945²/20)^(0.5)

The 95% CI = -2.6063 < μ₂ - μ₁ < 1.16025996668

By approximation, we have;

The 95% CI = -2.61 < μ₂ - μ₁ < 1.16

Given that the 95% confidence interval ranges from a positive to a negative value, we are 95% sure that the confidence interval includes '0', therefore, there is sufficient evidence that there is no difference between the two means, and the change in call waiting time is not statistically significant.

6 0
2 years ago
Other questions:
  • 7 hours to,mow 14 lawns<br> Rate= unit rate=
    6·2 answers
  • X is all of the following except
    14·1 answer
  • Can someone help me with number one please?
    14·2 answers
  • HELP ASAPPPPPP! I HAVE BEEN WAITING FOR 20 MIN PLS HELP ME! A prism and two nets are shown below: Image of a right triangular pr
    8·1 answer
  • Which piecewise defined function is shown on the graph?
    7·1 answer
  • Look at image. reflection across the x-axis​
    9·1 answer
  • 3. Is the relation {(1,2), (3, 10), (2,8), (5,<br> 10)} a function?<br> a) yes<br> b) no<br> a
    14·1 answer
  • What is the answer plz???
    10·1 answer
  • Nina and Luca were told to draw a net for the three-dimensional figure shown below. Which statement
    13·1 answer
  • The vertex of -5(x+2)^2-6
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!