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Debora [2.8K]
3 years ago
14

Find the distance between the two points rounding to the nearest tenth (if

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0

Answer:

<h2>9.8</h2>

Step-by-step explanation:

The distance is calculated using the formula d=√(x2-x1)²+(y2-y1)²

The first thing to do is subtract to find the necessary values.

X 8 - 4 = 4

Y -3 - 6 = -9

d=√(4)²+(9)²

d=√(16 + 81)

d=√97

d = 9.8488578018 or 9.8

Tom [10]3 years ago
6 0

Answer:

d = 9.8

Step-by-step explanation:

Use the distance formula.

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(4 - 8)^2 + (6 - (-3))^2

d = √(-4)^2 + 9^2

d = √97

d = 9.8

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Ahat [919]

Answer:

Cos θ  = -4/5

Tan θ = -3/4

Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

tan θ = -4/3, -3/4, 3/4, 4/3

==================================================

Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.

If sin θ =3/5

cos \  \theta =\sqrt{1-sin^2 \theta} = \sqrt{1-(\frac{3}{5} )^2} =\sqrt{1-\frac{9}{25} }=\sqrt{\frac{16}{25} } =\frac{4}{5}

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.

And

Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.

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3 years ago
Multiply. Express the product in simplest form. 2 over 10 times 20 equals n A. 40 B. 20 C. 4 D. 1 over 100
vredina [299]
The answer is choice A-40 :)
8 0
2 years ago
PLEASE HELPPP 10 points and will mark brainly!!!!!!
snow_tiger [21]

Answer:

-.095

Step-by-step explanation:

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2 years ago
At the end of the school year a school system has a table with the total absences and tardies in its 10 schools what is the best
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Step-by-step explanation:

3 0
2 years ago
The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0
2 years ago
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