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3 years ago

14

Find the distance between the two points rounding to the nearest tenth (if

2 answers:

Y_Kistochka [10]3 years ago

7 0

Answer:

<h2>9.8</h2>

Step-by-step explanation:

The distance is calculated using the formula d=√(x2-x1)²+(y2-y1)²

The first thing to do is subtract to find the necessary values.

X 8 - 4 = 4

Y -3 - 6 = -9

d=√(4)²+(9)²

d=√(16 + 81)

d=√97

d = 9.8488578018 or 9.8

Tom [10]3 years ago

6 0

Answer:

d = 9.8

Step-by-step explanation:

Use the distance formula.

d = √(x2 - x1)^2 + (y2 - y1)^2

d = √(4 - 8)^2 + (6 - (-3))^2

d = √(-4)^2 + 9^2

d = √97

d = 9.8

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Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

4

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$

The maximum is 4

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3 years ago

Someone help 6th grade math i will give brainliest

Soloha48 [4]

The first one is 64. The second one is -64. Third is 10000

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3 years ago

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Find the area. The formula is A=1/2bh

Lemur [1.5K]

Answer:

18

Step-by-step explanation:

1/2bh

9 x 4 = 36

36/2 = 18

area = 18

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3 years ago

There are 180 cars in the parking lot 30% are red cars how many red cards are there

Yuri [45]

There are 54 red cars

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2 years ago

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Can someone please answer this question please answer it correctly please show work

Zina [86]

Answer:

34) A

35) C

36) D

Step-by-step explanation:

34) The perimeter of a triangle is equal to the sum of the lengths of its sides

Sides: (6.2p + 4.5q) + (3.4p - 0.7r) + (2.9r - 4.1q)

Combine like terms (same variables)

(6.2p + 3.4p) + (4.5q - 4.1q) + (2.9r - 0.7r)

9.6p + 0.4q + 2.2r

A

35)

Time possibilities

1 hour - $3 - $5 = $-2 No

2 hours - $6 - $5 = $1 Yes

3 hours - $9 - $5 = $4 Yes

4 hours - $12 - $5 = $7 Yes

5 hours - $15 - $5 = $10 Yes

6 hours - $18 - $5 = $13 Yes

7 hours - $21 - $5 = $16 Yes

8 hours - $24 - $5 = $19 No

9 hours - $27 - $5 = $22 No

The possible hours that Ms. Barnes can park are 2 - 7 hours

The only inequality graph that represents all of these values is C

36)

<h3> $(-\frac{4}{7}) / (-\frac{3}{4}) * (-2\frac{1}{3})$ </h3>

Convert to improper fractions

<h3> $(-\frac{4}{7}) / (-\frac{3}{4}) * (\frac{-7}{3})$ </h3>

Divide by finding the reciprocal

<h3> $(-\frac{4}{7}) * (-\frac{4}{3}) * (\frac{-7}{3})$ </h3><h3 /><h3> $\frac{16}{21}$ * $-\frac{7}{3}$ </h3><h3 /><h3> $\frac{-16}{9}$ </h3>

Convert back to a mixed number

$-1\frac{7}{9}$

D

Hope this helps :)

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3 years ago