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nlexa [21]
3 years ago
15

PLEASEEEEEEEEEE HELPPPPPPP IM BEGGING :( (The first option is irrational, natural or whole /// third options are 2, 13.75 , or -

5/// third options are natural, irrational , or whole) thanks :')

Mathematics
1 answer:
Leona [35]3 years ago
5 0
1. whole
2.13.75
3. whole
I hope im right
and i hope i was usefull.
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Help with algebra question?
Charra [1.4K]
The system is 

i) \displaystyle{ \frac{-12+4y}{2x}-\frac{5x-6}{x}=-1

ii)\displaystyle{ 8^{5y-4}=8^{10x-4}


In the second equation, the bases are equal, so we make the exponents equal to set the equation:

                            5y-4=10x-4. This means that 5y=10x, that is y=2x.

 So, we can substitute y with 2x in the first equation:

\displaystyle{ \frac{-12+8x}{2x}-\frac{5x-6}{x}=-1.

Multiplying the second fraction by 2/2 and -1 by 2x/2x, we have:

\displaystyle{ \frac{-12+8x}{2x}-\frac{2(5x-6)}{2x}=-\frac{2x}{2x}.

Since the denominators are all equal, we can only work with the numerators, setting the equation:

-12+8x-10x+12=-2x, 

simplifying we get 0-2x=-2x, that is -2x=-2x, which is always true. (Here remember that x cannot be 0 since x was in the denominator).



This means that for any (x, y) such that y=2x, the system is satisfied.

We can check that the correct statements are:

3) The point (1, 2) is a solution. (Since we have y=2x).

6) The system has infinitely many solutions. (Since any pair (x, 2x) is a solution, except when x=0)
4 0
3 years ago
Solve:6x+2=2(x+4)-2<br> happy holidays!
shepuryov [24]

Answer:

x = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

6x + 2 = 2(x + 4) - 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute 2:                              6x + 2 = 2x + 8 - 2
  2. Combine like terms:                 6x + 2 = 2x + 6
  3. Subtract 2x on both sides:       4x + 2 = 6
  4. Subtract 2 on both sides;        4x = 4
  5. Divide 4 on both sides:            x = 1

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    6(1) + 2 = 2(1 + 4) - 2
  2. Multiply:                               6 + 2 = 2(1 + 4) - 2
  3. Add:                                     8 = 2(5) - 2
  4. Multiply:                               8 = 10 - 2
  5. Subtract:                              8 = 8

Here we see that 8 does indeed equal 8.

∴ x = 1 is the solution to the equation.

5 0
3 years ago
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