First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
- 109°, obtuse
- 131°, obtuse
- 53°, acute
- 124°, obtuse
Step-by-step explanation:
You are exected to know the relationships of angles created where a transversal crosses parallel lines.
- Corresponding angles are equal (congruent).
- Adjacent angles are supplementary, as are any linear pair.
- Opposite interior (or exterior) angles are equal (congruent).
The appearance of the diagram often gives you a clue.
You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.
1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.
2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.
3. Opposite interior angles are equal, so w will be 53°. It is acute.
4. Corresponding angles are equal, so x will be 124°. It is obtuse.
Substitute either set of points into the equation:
(3, -1) and (-6,-4)
-1= -5/9(3)+b
-1= -15/9+b
-1+5/3= -5/3 +5/3 +b
2/3=b
So,
f(x)= -5/9 (x) + 2/3
Argument
You have a total of 8 + 9 + 3 balls = 20
The first ball is 17/20 Probability that no ball drawn is red the first time
The Second ball is 16/19 Probability that no ball drawn is red the 2nd time
The third ball is 15/18 Probability that no ball drawn is red the 3rd time
Answer
Total Probability = 17/20 * 16/19 * 15/18 = 34/57
My calculator figures out fractions. You can do this just as easily with decimals.
0.85 * 0.8421 * 0.8333333 = 0.5964
34/57 = 0.5965 which is close enough.
If you have choices, choose the one that coincides with my answer. Otherwise use the decimal value.
