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3 years ago

Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are .

Mathematics

1 answer:

Alla [95]3 years ago

3 0

Answer:

Point B is (10 , -4)

Point D is (10/9 , 1)

Step-by-step explanation:

* Lets revise the rule of the point which divides of a line segment in

a ratio

- If point (x , y) divides the line segment AB, where A is (x1 , y1) and

B is (x2 , y2) in the ratio m1 : m2

∴ x = [m2(x1) + m1(x2)]/(m1 + m2)

∴ y = [m2(y1) + m1(y2)]/(m1 + m2)

* Now lets solve the problem

- Point C (3.6 , -0.4) divides AB in the ratio 3 : 2, where A is (-6 , 5)

# x = 3.6 , y = -0.4

# A is (x1 , y1) , B is (x2 , y2)

∴ x1 = -6 , y1 = 5

∵ m1 : m2 = 3 : 2

- Substitute these values in the rule

∵ x = [m2(x1) + m1(x2)]/(m1 + m2)

∴ 3.6 = [2(-6) + 3(x2)]/(3 + 2)

∴ 3.6 = [-12 + 3x2]/5 ⇒ multiply both sides by 5

∴ 18 = -12 + 3x2 ⇒ add 12 to both sides

∴ 30 = 3x2 ⇒ divide both sides by 3

∴ 10 = x2

* The x-coordinate of B is 10

∵ y = [m2(y1) + m1(y2)]/(m1 + m2)

∴ -0.4 = [2(5) + 3(y2)]/(3 + 2)

∴ -0.4 = [10 + 3y]/5 ⇒ multiply both sides by 5

∴ -2 = 10 + 3y2 ⇒ subtract 10 from both sides

∴ -12 = 3x2 ⇒ divide both sides by 3

∴ -4 = y2

* The y-coordinate of B is -4

∴ Point B is (10 , -4)

- Point D divides AB in the ratio 4 : 5 where A (-6 , 5) and B (10 , -4)

- To find the coordinates of point D use the same rule above

# D is (x , y)

# A is (x1 , y1) and B is (x2 , y2)

# m1 : m2 is 4 : 5

∵ x1 = -6 and y1 = 5

∵ x2 = 10 and y2 = -4

∵ m1 = 4 and m2 = 5

- Substitute these values in the rule

∵ x = [m2(x1) + m1(x2)]/(m1 + m2)

∴ x = [5(-6) + 4(10)]/(4 + 5) ⇒ multiply the numbers

∴ x = [-30 + 40]/9 ⇒ add

∴ x = [10]/9 ⇒ Divide

∴ x = 10/9

* The x-coordinate of D is 10/9

∵ y = [m2(y1) + m1(y2)]/(m1 + m2)

∴ y = [5(5) + 4(-4)]/(5 + 4) ⇒ multiply the numbers

∴ y = [25 + -16]/9 ⇒ add

∴ y = [9]/9 ⇒ Divide

∴ y = 1

* The y-coordinate of point D is 1

∴ Point D is (10/9 , 1)

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Answer:

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Step-by-step explanation:

For each 3-pointer shot, there are only two possible outcomes. Either the player makes it, or the player does not. The same is valid for free throws. This means that both the number of 3-pointers and free throws made are given by binomial distributions.

Since 3-pointers and free throws are independent, first we find the probability of making exactly 3 3-pointers out of 10, then the probability of making exactly 5 free throws out of 10, and then the probability that the player will make exactly 3 3-pointers and 5-free throws is the multiplication of these probabilities.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

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The chances of a basketball player hitting a 3-pointer shot is 0.4, which means that $p = 0.4$ . So this is $P(X = 3)$ when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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The probability of hitting a free-throw is 0.65, which means that $p = 0.65$ . The probability is $P(X = 5)$ when $n = 10$ .

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Calculate the probability that the player will make exactly 3 3-pointers and 5-free throws.

0.21499*0.15537 = 0.0334

0.0334 = 3.34% probability that the player will make exactly 3 3-pointers and 5-free throws.

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Step-by-step explanation:

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