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Vika [28.1K]
3 years ago
8

How do you solve 6x-2(x-3)

Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

0.629  or 0.795

Step-by-step explanation:

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The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
If ON = MN, find MN.
Furkat [3]
Use Pythagorean theorem.

[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}

Answer: |MN| = 4√2.
4 0
3 years ago
What does it mean when sampling is done without​ replacement? Choose the correct answer below. A. Once an individual is​ selecte
solmaris [256]

Answer:

The correct option is A) Once an individual is​ selected, the individual cannot be selected again.

Step-by-step explanation:

Consider the provided statement.

Without​ replacement mean each population sample unit has only one opportunity in the sample to be chosen.

For example:

If a bag contains 5 red and 3 white ball and you randomly select a white ball, the probability of selecting the white ball is 3/8.

Now if the experiment is done by without replacement that means the white ball (which you have selected) is no longer the part of the sample space.

Hence, we can say that once an individual is​ selected, the individual cannot be selected again.

Thus, the correct option is A) Once an individual is​ selected, the individual cannot be selected again.

8 0
3 years ago
What is the value of b2 - 4ac for the following equation? x(x 8) = 9
-BARSIC- [3]
If you would like to know the value of b^2 - 4 * a * c, you can calculate this using the following steps:

x * (x + 8) = 9
x^2 + 8x - 9 = 0
ax^2 + bx + c = 0

a = 1
b = 8
c = - 9

D = <span>b^2 - 4 * a * c = 8^2 - 4 * 1 * (-9) = 64 + 4 * 9 = 64 + 36 = 100

The correct result would be 100.</span>
4 0
3 years ago
Please help with this one. I will give brainliest!!
qaws [65]

Answer: 78.54

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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