$1;\ \frac{1}{32};\ \frac{1}{243};\ \frac{1}{1024};\ \frac{1}{3125}\\\\1=\frac{1}{1^5}\\\\\frac{1}{32}=\frac{1}{2^5}\\\\\frac{1}{243}=\frac{1}{3^5}\\\\\frac{1}{1024}=\frac{1}{4^5}\\\\\frac{1}{3125}=\frac{1}{5^5}\\\vdots\\\\a_n=\frac{1}{n^5}\ where\ n\in\mathbb{N^+}$

5 0

3 years ago

Which is a correct two column proof. Given <4 and

vladimir1956 [14]

The initial statement is: QS = SU (1)

QR = TU (2)

We have to probe that: RS = ST

Take the expression (1): QS = SU

We multiply both sides by R (QS)R = (SU)R

But (QS)R = S(QR) Then: S(QR) = (SU)R (3)

From the expression (2): QR = TU. Then, substituting it in to expression (3):

S(TU) = (SU)R (4)

But S(TU) = (ST)U and (SU)R = (RS)U

Then, the expression (4) can be re-written as:

(ST)U = (RS)U

Eliminating U from both sides you have: (ST) = (RS) The proof is done.

4 0

2 years ago

What is the first step in solving the equation x2 - 25 = 0?

Finger [1]

Answer:

first step - make x² the subject of the formula

x² = 25

second step :

find the square root of both sides

√x² = √25

x = 5

Step-by-step explanation:

5 0

2 years ago