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brilliants [131]
3 years ago
7

Which of the following smoothing constants would make an exponential smoothing forecast equivalent to a last-value forecast? Sel

ect one: a. 0. b. 0.01. c. 0.1. d. 0.5. e. 1.
Mathematics
1 answer:
cestrela7 [59]3 years ago
7 0

Answer: e. 1

Step-by-step explanation: a key problem in exponential smoothing is the choice of the values used for smoothing constants. It is easy to understand and quite easy to use, making it one of the most popular methods for forecasting. The forecast Ft+1 for the upcoming period is the estimate of average level Lt at the end of period t.

where α, the smoothing constant, is between 0 and 1. We can interpret the new forecast as the old forecast adjusted by some fraction of the forecast error. The new estimate of level as a weighted average of Dt (the most recent information on average level) and Ft (our previous estimate of that level). Lt (and Ft+1 ) can be written in terms of all previous demand.

Thus, Ft+1 is a weighted average of all previous demand with the weight on Di given by α(1-α)t-i where t is the period

that just ended. As t increases the sum of these weights tends to 1.

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sara has two bags of nuts one with 60% peanuts and the other with 28% peanuts. to make a ten pound bag of 45% peanuts how much o
Drupady [299]

SOLUTION - GIVEN = Sara has two bag with 60% & 28% peanut.

                    prove = How much the peanut is used to make 10 pound of 45%

                                 peanut.

TO PROOF -  Assume that

                    let  x be the  value of the peanut  used by sara  from the bag

                  60% peanut bag.

                  let ( 10 - x)  be the value of peanut used by sara from 28% peanut

                  bag.

                as given the bag become  of  the 10 pound which contain

                 45% of peanunt.

                  thus we have

               0.60x + 0.28 ( 10 - x ) = 0.45 (10)        

                0.60x + 0.28 ( 10 -x ) =   4.5

               0.60x  +   2.8 -  0.28 x = 4.5

              0.60x - 0.28x = 4.5 - 2.8

            0.32x  = 1.7

             x =  5.3125   peanut is taken from the 60% bag.

            & 4.6875 peanut from the 28% bag.                                              

4 0
2 years ago
Multiply.
DanielleElmas [232]

Answer & Step-by-step explanation:

<em>(x² - 5x)(2x² + x - 3)</em>

Multiply each term from the first expression into the second expression.

<em>2x⁴ + x³ - 3x² - 10x³ - 5x² + 15x</em>

Combine like terms.

<em>2x⁴ - 9x³ - 8x² + 15x</em>

So, after you multiply the expressions, your answer will be 2x⁴-9x³-8x²+15x.

7 0
3 years ago
In 2007, there were more than 8.14 million cars for sale. Over the next 3 years, the number of cars decreased by 23%. Write an e
Nina [5.8K]

Answer:

c = 8.14 million×(0.9166)^t

4.83 million  

Step-by-step explanation:

Data:

  t = y - 2007

c₀ = 8.14 million

c₃  = 23 % less than c₁

Part 1. Calculate c₃

c₃ = c₀(1 - 0.23) = 0.77c₀

Part 2. Calculate r

      c₃ = c₀r^t

0.77c₀ = c₀r³

   0.77 = r³              Divided each side by c₀

         r = 0.9166     Took the cube root of each side

The explicit decay model is c = 8.14 million×(0.9166)^t

Part 3. Prediction

t = 2013 - 2007 = 6

c = c₀r^t = 8.14 million×(0.9166)⁶ = 8.14 million × 0.5929 = 4.83 million

The model predicts that there will be 4.83 million cars for sale in 2013.

7 0
2 years ago
Round the decimal to the nearest hundredths 983.625
r-ruslan [8.4K]
983.625
9 = hundreds
8 = tens
3 = ones
6 = tenths
2 = hundredths
5 = thousandths
You want to round to the nearest hundredths
Look at the number on the right, if it's bigger than 5, round up, if it's 4 or lower, round down.
In this case, the number to the right is a 5, so you round the 2 (hundredths) up one so:
<span>983.63</span>
5 0
3 years ago
Determine the center and scale factor for the dilation shown below
iren2701 [21]
A center at q scale factor of 1/2
3 0
3 years ago
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