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brilliants [131]
4 years ago
7

Which of the following smoothing constants would make an exponential smoothing forecast equivalent to a last-value forecast? Sel

ect one: a. 0. b. 0.01. c. 0.1. d. 0.5. e. 1.
Mathematics
1 answer:
cestrela7 [59]4 years ago
7 0

Answer: e. 1

Step-by-step explanation: a key problem in exponential smoothing is the choice of the values used for smoothing constants. It is easy to understand and quite easy to use, making it one of the most popular methods for forecasting. The forecast Ft+1 for the upcoming period is the estimate of average level Lt at the end of period t.

where α, the smoothing constant, is between 0 and 1. We can interpret the new forecast as the old forecast adjusted by some fraction of the forecast error. The new estimate of level as a weighted average of Dt (the most recent information on average level) and Ft (our previous estimate of that level). Lt (and Ft+1 ) can be written in terms of all previous demand.

Thus, Ft+1 is a weighted average of all previous demand with the weight on Di given by α(1-α)t-i where t is the period

that just ended. As t increases the sum of these weights tends to 1.

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Set x^4 − 6x^3 + 22x^2 − 48x + 40 equal to 0. x^4 − 6x^3 + 22x^2 − 48x + 40 = 0

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(x − 2) (x^3 − 4x^2 + 14x − 20) = 0

 Factor x^3 − 4x^2 + 14x − 20 using the rational roots test.

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 Combine like factors.

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If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

(x − 2)^2 = 0

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Set (x − 2)^2 equal to 0.

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Set x^2 − 2x + 10 equal to 0. x^2 − 2x + 10 = 0

Solve x^2 − 2x + 10 = 0 for x.

Use the quadratic formula to find the solutions.

−b ± (√b^2 − 4 (ac) )/2a

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2 ± (√(−2)^2 − 4 ⋅ (1 ⋅ 10))/2 ⋅ 1

Simplify.

Simplify the numerator.

  x =    2 ± 6i/ 2.1

Multiply 2 by 1

 x =  2 ± 6i/2⋅1

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The final answer is the combination of both solutions.

x = 1 + 3i, 1 − 3i

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