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Lelu [443]
3 years ago
11

In a statewide lottery, one can buy a ticket for $1. With probability .0000001, one wins a million dollars ($1,000,000), and wit

h probability .9999999 one wins nothing ($0). Let Y denote the winnings from buying one ticket. Construct the probability distribution for Y. Show that the mean of the distribution equals .10, corresponding to an expected return of 10 cents for the dollar paid.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0

Using the expected value, it is found that the mean of the distribution equals $0.1.

  • The expected value, which is the mean of the distribution, is given by <u>each outcome multiplied by it's probability</u>.

The probabilities of <u>each outcome</u> are:

  • .0000001 probability of earning $1,000,000.
  • .9999999 probability of earning $0.

Thus, the mean is given by:

E(Y) = 0.0000001(1000000) + 0.9999999(0) = 0.1

Thus showing that the expected value is $0.1.

A similar problem is given at brainly.com/question/24855677

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3 years ago
The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.
Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

y = 2.89\sin(0.0145x-1.40) + 10.99.

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

days = 52

So:

x = 52

So, we have:

y = 2.89\sin(0.0145x-1.40) + 10.99.

y = 2.89\sin(0.0145*52-1.40) + 10.99.

y = 2.89\sin(0.754-1.40) + 10.99.

y = 2.89\sin(-0.646) + 10.99.

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y = -1.740 + 10.99.

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<em></em>y = 9.3<em> --- approximated</em>

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