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Lelu [443]
3 years ago
11

In a statewide lottery, one can buy a ticket for $1. With probability .0000001, one wins a million dollars ($1,000,000), and wit

h probability .9999999 one wins nothing ($0). Let Y denote the winnings from buying one ticket. Construct the probability distribution for Y. Show that the mean of the distribution equals .10, corresponding to an expected return of 10 cents for the dollar paid.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0

Using the expected value, it is found that the mean of the distribution equals $0.1.

  • The expected value, which is the mean of the distribution, is given by <u>each outcome multiplied by it's probability</u>.

The probabilities of <u>each outcome</u> are:

  • .0000001 probability of earning $1,000,000.
  • .9999999 probability of earning $0.

Thus, the mean is given by:

E(Y) = 0.0000001(1000000) + 0.9999999(0) = 0.1

Thus showing that the expected value is $0.1.

A similar problem is given at brainly.com/question/24855677

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Find the equation of a circle that has its center at (-4, 3) and has a radius of 5. (x + 4) 2 + (y - 3) 2 = 25
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Answer:

(x+4)^2 + (y-3)^2 = 25

Step-by-step explanation:

You can use the center of a circle to write an equation in vertex form. Vertex form is (x-h)^2+(y-k)^2 = r^2 and the vertex is (h,k). Notice (h,k) are the opposite sign in the equation then as the point.

Here h = -4 and k = 3. Substitute these values and the value r = 5.

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Overeating for just four weeks can increase fat mass and weight over two years later, a Swedish study shows.^1 Researchers recru
bezimeni [28]

Answer: [a] 95% confidence interval = 4.4 < Ẍ <9.2

               [b] margin of error = ± 2.4

Step-by-step explanation:

here let us carefully look into this problem,

from the question, we have that  Ẍ  = 6.8, and SE = 1.2

let us begin

(a). asked to calculate the 95% confidence interval we have;

       95% C.I = Ẍ ±  2 (SE) = 6.8 ±  2(1.2) = 6.8 ±  2.4

        95% C.I = (4.4, 9.2)

this gives the confidence interval to be (4.4 < Ẍ < 9.2).

(b). the error margin is ±  2.4, which implies that our estimate of 6.8 pounds is within 2.4 pounds of the true mean weight gain for the population.

cheers i hope this helped a great deal !!1

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3 years ago
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