1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotegsom [21]
3 years ago
14

b%7D%5E%7B%20-%201%7D%20%7D%20" id="TexFormula1" title=" \frac{ {a}^{ - 1} + {b}^{ - 1} }{ {b}^{ - 1} } " alt=" \frac{ {a}^{ - 1} + {b}^{ - 1} }{ {b}^{ - 1} } " align="absmiddle" class="latex-formula">
how do I solve this?​
Mathematics
1 answer:
Olegator [25]3 years ago
5 0

Answer:

  \dfrac{a+b}{a}

Step-by-step explanation:

There is nothing to solve. Perhaps you want to simplify the expression.

  \dfrac{a^{-1}+b^{-1}}{b^{-1}}=\dfrac{b(a^{-1}+b^{-1})}{b(b^{-1})}=\dfrac{b}{a}+1=\boxed{\dfrac{a+b}{a}}

_____

The applicable rules of exponents are ...

  b^-1 = 1/b

  (a^b)(a^c) = a^(b+c)

You might be interested in
If AABC = ADEC,<br> LC = 55°, ZD = 65°, and ZB = 2x<br> D<br> С<br> В B.<br> x = [?]
elena55 [62]

Answer:

x = 30

Step-by-step explanation:

65 + 55 = 120

angle B must equal 60

angle B is labeled as 2x

set up equation to solve for 'x':  2x = 60

                                                     x = 30

add up all angles to make sure you get 180 degrees

6 0
3 years ago
Leslie gets paid $9 per hour and received a $100 bonus.​
natta225 [31]

Answer:

so whats the question??

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Miss Allen read for 3/4 of an hour less than the student who read the most. How long sis Miss Allen read for?
kolbaska11 [484]

Answer:

See Explanation

Step-by-step explanation:

Given

Allen = \frac{3}{4}hr less than the most hour

Required

Hours read by Miss Allen

The question is incomplete, as the hours read by each student is not given.

To solve this, I will assume that the longest hours read by a student is x.

So, the expression for Miss Allen will be:

Allen = x - \frac{3}{4}hr

Assume that x = 1hr

The expression becomes

Allen = 1hr - \frac{3}{4}hr

Take LCM and solve

Allen =\frac{4 - 3}{4}hr

Allen =\frac{1}{4}hr

7 0
3 years ago
Two rectangles have the same area of 24cm².The second rectangle is 4cm shorter and 1cm wider than the first.What is the length a
lukranit [14]

Answer:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

Step-by-step explanation:

You can examine factor pairs of 24 to see which pairs meet the requirements:

  24 = 1×24 = 2×12 = 3×8 = 4×6

Factor pairs (2, 12) and (3, 8) have one factor that differs by 1 and another factor that differs by 4. We can use these numbers to describe the rectangles:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

5 0
3 years ago
two weeks ago, James bought 3 cans of tennis balls. last week, he bought 4 cans of tennis balls. the tennis balls cost d dollars
Jet001 [13]

Answer:$ 2.25

Step-by-step explanation:4can +3Cans=7cans so divide 15.75 by 7 so the answer is 2.25


6 0
3 years ago
Other questions:
  • Hey guys, im new to this so can you plz help me out on this question and explain a bit plz:
    9·1 answer
  • The whole number 140 is divisible by 2, 3, 4, 5, 7, and 10.<br><br><br> True or False
    8·2 answers
  • A crew of highway workers paved 2/15 mile in 20 minutes. if they worked at the same rate, what portion of a mile will they pave
    7·1 answer
  • Hello I am asking this question What is 25% of £90
    5·1 answer
  • Jane and john shared some money such that jane got 4 times as much money as john. What fraction of money did john get ?​
    11·1 answer
  • HELP ASAP PLEASE
    14·2 answers
  • ∠w = <br> plzz help!!!!! due today
    9·2 answers
  • DO NOT SEND ME PDFS OR I WILL REPORT ANSWER CORRECTLY FOR BRAINLIEST
    10·2 answers
  • What is 5.316 ÷ 1.942 (long divison)
    8·2 answers
  • Use slope to determine if lines AB and CD are parallel, perpendicular, or neither 7. 4(5.-8), B(-2,-10), C(-6, -13). D(-2. 1)m(A
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!