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Anna71 [15]
3 years ago
12

If AABC = ADEC, LC = 55°, ZD = 65°, and ZB = 2x D С В B. x = [?]

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

x = 30

Step-by-step explanation:

65 + 55 = 120

angle B must equal 60

angle B is labeled as 2x

set up equation to solve for 'x':  2x = 60

                                                     x = 30

add up all angles to make sure you get 180 degrees

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Johnny earns $5 per day delivering newspapers. What equation shows how much money m he earns delivering papers for d days?
jeyben [28]
Hello there,

Your correct answer would be C.) m=5d.


The reason is so because 5 and d are going to be multiplied and so sence they would be multiplied this mean's that you will see how much money he earned in (m) days.

Correct answer would be "C.) m=5d"

Hope this helps!
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Find value of k
insens350 [35]

Answer:

k=10BY DPING PROCESS IT BECOME

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Richelle drew hexagon KLMNOP. She thinks that the angles are congruent. How can she show that the angles are congruent without u
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Richelle can fold a hexagon in half and if they match up they will be congruent.
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6 0
3 years ago
4. Meagan invests $1,200 each year in an IRA for 12 years in an account that earned 5%
Nina [5.8K]
Part A)

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &1200\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}

\bf A=1200\left[ \cfrac{\left( 1+\frac{0.05}{1} \right)^{1\cdot  12}-1}{\frac{0.05}{1}} \right]\implies A\approx 19100.55

part B)

so, for the next 11 years, she didn't make any deposits on it and simple let it sit and collect interest, compounded annually at 5%.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\  
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$19100.55\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &11
\end{cases}
\\\\\\
A=19100.55\left(1+\frac{0.05}{1}\right)^{1\cdot  11}\implies A\approx 32668.42

part C)

well, for 12 years she deposited 1200 bucks, that means 12 * 1200, or 14,400.

now, here she is, 12+11, or 23 years later, and she's got 32,668.42 bucks?

all that came out of her pocket was 14,400, so 32,668.42 - 14,400, is how much she earned in interest.
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4 years ago
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