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RoseWind [281]
3 years ago
10

MARKING AS BRAINLIEST!!!

Biology
2 answers:
PtichkaEL [24]3 years ago
8 0

Answer:

C

Explanation:

The number of ATPs formed in the Krebs Cycle is 34 while in Glycolysis is 4. Adding the two result in 38 ATPs. However, remember that Glycolsysis takes up an initial 2 ATPs before the 4 are produced. The net ATP production in glycolysis is, therefore (4 – 2) = 2 ATPs. The overall net production of ATPs in aerobic cellular respiration is therefore 36 ATPs.

makvit [3.9K]3 years ago
4 0

Answer:

The answer is C.)36

Explanation:

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Interstitial flood bath and surround the cells; present outside the cell

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Intracellular fluid: The solutions which are present inside the cell

Extracellular fluids: The solutions that are present outside the cell

Extracellular fluid consists of plasma, interstitial, and transcellular fluid

Interstitial fluid; The fluid that is present in cells spaces and capillaries. It contains the nutreints that are secreted by capillaries through osmosis and metabolic waste of cells.

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0 just count all the atoms

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Need it done as fast as you can it's do in 4 hours.
vagabundo [1.1K]

Answer no 1:

             sW         sW           sw          sw

Sw    SsWw       SsWw      Ssww    Ssww

Sw    SsWw      SsWw     Ssww      Ssww

sw   ssWw       ssWw      ssww      ssww

sw   ssWw      ssWw        ssww     ssww

The genotype of the parents will be Ssww and ssWw.

About 4/16 offsrings will have the genotype SsWw, 4/16 will have the genotype Ssww. 4/16 will have the gentype ssWw. 4/16 will have the genotype ssww.

About 25% will have the phenotye, smooth and wooly. About 25% will have the phenotype smooth and non wooly. About 25% will have the phenotype non- smooth and wooly. About 25 % will have the phenotype non-smooth and non- wooly.

Answer No 2)

            bT             bT              bT            bT

Bt     BbTt           BbTt           BbTt         BbTt

Bt     BbTt           BbTt           BbTt         BbTt

Bt     BbTt           BbTt           BbTt         BbTt

Bt     BbTt           BbTt           BbTt         BbTt

The genotype of the parents will be BBtt and bbTT.

As seen in the punnet square, the phenotype of all the offsprings born from such a cross will be black trotter.

Answer No 3)

             wd          wd           wd           wd

WD    WwDd    WwDd     WwDd     WwDd

WD   WwDd    WwDd     WwDd     WwDd

WD   WwDd    WwDd     WwDd     WwDd

WD   WwDd    WwDd     WwDd     WwDd

The genotype of the parents will be WWDD and wwdd.

The results of the punnet square illustrate that all of the offsprings will have white flower colour and disc shaped fruit.

Answer No 4)

The phenotypes of the rabbits will be as follows:

Ggbb - Gray hair and red eyes.

ggBB- White hair and black eyes

ggbb - White hair and red eyes.

GgBb - Gray hair and black eyes

Answer No 5)

           Gb        Gb          Gb         Gb

gB     GgBb     GgBb      GgBb    GgBb

gB     GgBb     GgBb      GgBb    GgBb

gb     Ggbb      Ggbb     Ggbb    Ggbb

gb     Ggbb      Ggbb     Ggbb    Ggbb

8 out of 16 offspring will have Gray fur and black eyes.

8 out of 16 will have gray fur and red eyes.

0 out of 16 will have white fur and black eyes.

0 out of 16 will have white fur and red eyes.

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