To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meter s more than the distance she walked north. If Sindy were able to walk directly from the post office to the library in a straight line, she would have walked 150 meters. Suppose x represents the distance Sindy walked north. Which equation can be used to find x? x^2+(x+20)^2=150^2
202=x^2-150^2
x+(x+20)=150
x^2+(x+150)^2=20^2
2 answers:
A. x∧2+(x+20∧2=150∧2 is correct. because you need to plug the numbers into the pathagoreum theorum which is a∧2+b∧2=c∧2 150 is our c because it is the side right accross from the right angle. which number is a and which number is b does not matter. x is the distance north so we can assign that to a and the distace east is north plus 20 so we can assign b to x+20.
Answer:
150 is our c because it is the side right accross from the right angle.
which number is a and which number is b does not matter.
x is the distance north so we can assign that to a and the distace east is north plus 20 so we can assign b to x+20.
a. x∧2+(x+20∧2=150∧2 is correct.
because you need to plug the numbers into the pathagoreum theorum which is
a∧2+b∧2=c∧2
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