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sergejj [24]
3 years ago
13

Step by step on how to do this

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0
60÷24= 2.5
50÷20= 2.5
if both have 2.5 then that means that 30÷2.5= to line AC which would be 12
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Garrett buys tickets to a concert. He pays $24.50 for each ticket plus a
Kay [80]

24.50 x 8.50 = 33.0

131 ÷ 33 = 3.9696969697

8 0
3 years ago
Which number is in the solution set of this equation? 7x − 9 = 40
skad [1K]

Answer: the answer is 7

Step-by-step explanation: add 9 to both sides, eliminating -9 so now you have 7x=49 divide both by 7 and you get x= 7 check it by inputing 7 for x, 7(7)-9=40

7(7)=49 next 49-9= 40

it checks out, so x= 7

7 0
3 years ago
Short cut method to mulitply 12 by 50
liberstina [14]

Answer:

12 * 50 = 600

Step-by-step explanation:

We have to multiply 12 by 50

<u>Short cut method for multiplying a number by 50</u>

Step 1: Take the half of the given number

Step 2: Multiply the result by 100

<u>To find the short cut method to multiply 12 by 50</u>

Here the number is 12

Step 1: divide the number by 2

12/2 = 6

Step 2: Multiply 6 by 100 we get 600

Therefore 12 * 50 = 600

4 0
3 years ago
Read 2 more answers
Help needed rn i have a few minutes left
aleksandr82 [10.1K]

Answer:A

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A Ferris Wheel 22.0m in diameter rotates once every 12.5s. What is the ratio of a persons apperenet weight to her real weight (a
AnnZ [28]
  <span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed: 
a = omega^2*r 

omega and r in terms of given data: 
omega = 2*Pi/T 
r = d/2 

Thus: 
a = 2*Pi^2*d/T^2 

What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
Weight (m*g): downward 
Normal force (Ntop): upward 

Thus Newton's 2nd law reads: 
m*g - Ntop = m*a 

At top (acceleration is upward): 
Weight (m*g): downward 
Normal force (Nbottom): upward 

Thus Newton's 2nd law reads: 
Nbottom - m*g = m*a 

Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
Ntop = m*(g - a) 
Nbottom = m*(g + a) 


Substitute a: 
Ntop = m*(g - 2*Pi^2*d/T^2) 
Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2) 
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
d:=22 m; T:=12.5 sec; g:=9.8 N/kg; 

Results: 
Ntop/(m*g) = 71.64%...she feels "light" 
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
7 0
3 years ago
Read 2 more answers
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