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3241004551 [841]
4 years ago
6

Chen receives 17.5% of 4 weeks normal pay as leave loading. If Chen’s leave loading was $379.40 find his normal weekly pay

Mathematics
1 answer:
galina1969 [7]4 years ago
3 0
Hope this helps ......

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ANSWER THIS ALEGBRA QUESTION IF YOU ARE GREAT AT MATH ‼
Eduardwww [97]

Answer:

C) (5, ∞)

General Formulas and Concepts:

<u>Alg I</u>

  • Range is the set of y-values that are outputted by function f(x).

Step-by-step explanation:

According to the graph, we have a horizontal asymptote at y = 5. Therefore, the graph never actually <em>touches/reaches</em> the y-value 5. Therefore, 5 is not included in our range:

(5, ∞) or y ≥ 5

3 0
3 years ago
First answer gets brainliest!
vagabundo [1.1K]

Answer:

the answer is 6561m^4

Step-by-step explanation:

9^4 = 9^4m^4

9^4=6561

6561m^4

7 0
3 years ago
If y varies directly as x and y =6 when x =2 ... find y when x=9
nevsk [136]

Answer:

27

Step-by-step explanation:

y = kx, where k is the constant of proportionality.  If x = 2 and y = 6, that constant is determined as follows:

6 = k(2), or k = 3.  Then y = 3x.  When x = 9, y = 27

4 0
3 years ago
−8x−10=4x+14 what’s x
Mkey [24]

Answer:

i think it's:

Step-by-step explanation:

x=-2

6 0
2 years ago
Read 2 more answers
Use the position equation given below, where s represents the height of the object (in feet), v0 represents the initial velocity
iris [78.8K]

Answer:

(a) 7.5 seconds

(b) The horizontal distance the package  travel during its descent is 1737.8 ft

Step-by-step explanation:

(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀

The initial height of the object s₀ = 900 feet

The initial vertical velocity of the object v₀_y = 0 m/s

The time it takes the package to strike the ground is found as follows;

0 = -16·t² + 0×t + 900

900 = 16·t²

t² = 900/16 = 62.25

t = √62.25 = 7.5 seconds

(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have

158 miles/hour = 231.7126 ft/s

The horizontal distance the package  covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place

The horizontal distance the package  travel during its descent = 1737.8 ft.

4 0
3 years ago
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